Hello again everyone!

I'm going through Hot Dog's tutorial on asm right now and I have encountered a slight problem. Working with variables, ld doesn't want to set a register. In the snippet below, the first line will work but the second one will not. Is there something I skipped over accidentally?

ld a, (var1)
ld b, (var1)
The error spasm outputs:
Pass one...
learn2.asm:7: warning: Suggest remove extra parentheses around argument
Pass two...
learn2.asm:7: warning: Number is too large to fit in 8 bits, truncating
Done


Here is the code

;Multiplication program
#include "ti83plus.inc"
.org $9d93
.db t2ByteTok, tAsmCmp
B_CALL _ClrLCDFull
ld a, (Mula) ;Holds the answer
ld b, (Mulb) ;How many times to multiply
ld c, a      ;What to add every time it multiplies, or else it will do powers


BeginLoop:
add a, c
djnz BeginLoop ;Remember that the b is decresed before it checks
ld h, 0
ld l, a

B_CALL _DispHL

ret


Mula:
.db 5

Mulb:
.db 5




Thanks!


Edit:
Found the answer! For those who look at this in the future, you can only use register a to retrieve data. You need to store the memory address in hl for other registers.

There is also another cool trick the same size and speed almost the same speed as Hot_Dog's suggestion but destroys the value of 'c' instead of 'a' (in case you need to preserve a).

ld bc,(var1-1)
This works because 2 byte numbers are stored as little endian in memory.

Oops yeah, you're right, I was thinking of hl.  Fixed.

There is also another cool trick the same size and speed almost the same speed as Hot_Dog's suggestion but destroys the value of 'c' instead of 'a' (in case you need to preserve a).

Code: [Select]

ld bc,(var1-1)
This works because 2 byte numbers are stored as little endian in memory.

That's one of those tricks that totally makes sense but someone like me forgets about