So, I have started learning Z80 ASM again and I have a question...
In a user program, I know that the first two bytes are size bites, are the next 8 or less the name?, if it is is it null terminated.
Then say I wanted to get the first "line" of the program how would I do that, I've been doing some testing and it hasnt worked out( I think because of something in the first two lines of what I wrote).

If you want to edit the first byte, you can try this:
     ld hl,NAME
     rst rMOV9TOOP1
     bcall(_ChkFindSym)
     ret c                ;The program doesn't exist, so exit
     ex de,hl
;Just checking to make sure the size isn't zero, otherwise it will edit unknown data
     ld a,(hl)
     inc hl
     or (hl)
     ret z
     inc hl
     ld (hl),30h     ;or whatever byte you want
     ret
NAME:
     .db 5,"HELLO",0 ;5 means program, 0 terminates
If you want to see more complicated code that edits the first byte of the second line:
     ld hl,NAME
     rst rMOV9TOOP1
     bcall(_ChkFindSym)
     ret c
     ex de,hl
;Just checking to make sure the size isn't zero, otherwise it will edit unknown data
     ld c,(hl)
     ld a,c
     inc hl
     or (hl)
     ret z
     ld b,(hl)
     inc hl
;BC is now the size of the program
;HL points to the data
     ld a,3Fh        ;3Fh is the newline token
     cpir            ;Search a max of BC bytes at HL for the first instance of A
     ret po          ;No bytes left in the program
;HL now points to the byte after the start of the second line
;Make sure it isn't another newline. (means Line 2 was empty)
     cp (hl)
     ret z
     ld (hl),30h     ;or whatever byte you want
     ret
NAME:
     .db 5,"HELLO",0