Does that mean I have to count aalll the numbers?

If the program returns a string just do Length(String)

'nother bitmap question: Am I right that you are using a custom routine now?
Also does bitmap clip?

Well, I need to find another way for 24x24s

Putting them into a pic and uploading to calc distorts it
Jacobly converted one of my big sprites but I don't want to bother him with another
Or if I write down the binary for the 576 pixels then use a hex converter, but 576 seems like a lot

I think
appvBLAH->W
{W}^r->A
{W+2}^r->B
{W+4}^r->C

I think
appvBLAH->W
{W}->A
{W+1}->B
{W+2}->C
Works with 1 byte tho


ALSO
Are tilemaps usually slow?
The speed of the program is about 25-35% the speed of what it was before

Like what?
I don't think its displaying the entire tilemap at one time, but just what will be on the screen.

Nope, thats out of the loop
(same conversation's going on in grappler topic )

I'll go get code I guess

Fill(L5,5,0)
8->{L5}
24->{L5+1}
GDB1->C
Repeat getKey(15)
   ClrDraw
   0-({L5}^8)->{L5+2}
   For(N,{L5}/8-1,{L5}/8+11)
      0-({L5+1}^8)->{L5+3}
      For(D,{L5+1}/8-1,{L5+1}/8+11
         If {D*24+N+C}->{L5+4}
            Pt-On({L5+2},{L5+3},{L5+4}-1*8+Pic0)
         End
         {L5+3}+8->{L5+3}
      End
      {L5+2}+8->{L5+2}
   End
   If getKey(41)
      {L5}++
   End

Any visible major unoptimizations?

Well, I need to find another way for 24x24s

Putting them into a pic and uploading to calc distorts it
Jacobly converted one of my big sprites but I don't want to bother him with another
Or if I write down the binary for the 576 pixels then use a hex converter, but 576 seems like a lot

You know... its not that hard to write a converter program yourself in Axe.  Say you had 8 24x24 sprites drawn to a pic on your calculator side by side.  Let's convert the Nth picture to a 148 digit hex string in the OS Str1:

:.CONVERT
:.This number can be 0-7 to distinguish the pictures
:0→N
:
:.Read from Pic1 and create the string variable Str1
:Return!If GetCalc("Pic1")→P
:Return!If GetCalc("Str1",148)→S
:
:.Add the size bytes to the bitmap
:Copy(_E1818>Hex,S,4)
:S+4→S
:
:.Use N to find the first byte of the picture
:N^4*3+(N/4*288)+P→P
:
:.Iterate through all the rows of the sprite
:For(24)
:  .Copy the 6 hex digits of 1 row to the string
:  Copy({P}^rr>Hex,S,4)
:  Copy({P+2}^rr>Hex,S+4,2)
:
:  .Increment the position in the picture and the string
:  S+6→S
:  P+12→P
:End