Quote from: epic7 on December 17, 2011, 12:51:07 pm

getKey(2)?X--

Evidently not, when I tried something like that it threw an error at compile-time.

I get no such error, and there should be no difference between the two syntaxes. You mentioned something about Pt-X commands not working in them, and this is true, but not because of a syntax difference. It's because Axe requires that some comamnds start a line, and the Pt-X commands are among them, so you can't use them mid-line in an inline conditional.

A ? is an "if and only if" statement, right?

Like the first word of a sentence

Ok, I guess there is a lot of differences since there's lots of commands starting with capitals.

Yes. X?Y produces the same code as If X : Y : End, and X?Y,Z produces the same code as If X : Y : Else : Z : End.

I have a question: why doesn't this code work? (It compiles, but it glitches on me)
0→{S}→{S+5}→{S+15}
and S is the pointer to appvar.

(I just had this happen to me too and I spent a couple of hours before getting Runer's help and facepalming.)

Because of the way Axe optimizes, number→{pointer} returns the pointer instead of the number.  The code equivalent to what you are doing is actually this:
:0→{S} :S→{S+5} :S+5→{S+15}

If you're wondering, the optimized way to do that would be:

and 0→{→{→{S}+5}+10}

question from the former code: what does that "and" do?

Since →{} stores only the lower eight bits (one byte), it doesn't matter what the high byte of HL is as long as the low byte is zero. In other words, all we need is for the last eight bits of HL to be zero. and 0 does a bitwise AND on the last eight bits of HL, which looks like this:

     ****************     // Original value of HL; * is either 0 or 1
 and         00000000     //  and 0
     ********00000000     // Final value of HL

And that's all that's needed to store one byte of zero to {S}. It's also one byte smaller than just using 0 (LD L,0 versus LD HL,0), which is why Runer112 uses it.

Clever optimization there