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Author Topic: Axe Q&A  (Read 600280 times)

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Offline Darl181

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Re: Axe Q&A
« Reply #1290 on: January 08, 2012, 01:07:27 am »
No, Text() can only write to L6.  It's hard-coded into the routine.
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Offline parserp

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Re: Axe Q&A
« Reply #1291 on: January 08, 2012, 01:09:23 am »
Quote from: Darl181 on January 08, 2012, 01:07:27 am
No, Text() can only write to L6.  It's hard-coded into the routine.
Dang. I'll have to do some tricky buffer copying. :)
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Offline Quigibo

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Re: Axe Q&A
« Reply #1292 on: January 08, 2012, 03:34:17 am »
Blame TI for that.  If you want to draw directly to the back-buffer, you'd have to make your own font routine, which is easy, but takes forever to get all those letter/number/symbol sprites as well as a lot of space in the program itself.  But sometimes a kick-ass font can really improve a game's look! :D
« Last Edit: January 08, 2012, 03:34:40 am by Quigibo »
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Offline Darl181

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Re: Axe Q&A
« Reply #1293 on: January 08, 2012, 03:19:15 pm »
With Z-Select, does it Goto the label or does it run it as a subroutine?
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Offline Builderboy

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Re: Axe Q&A
« Reply #1294 on: January 08, 2012, 07:44:45 pm »
Quote from: jacobly on January 07, 2012, 10:24:50 am
Quote from: Builderboy on January 06, 2012, 10:57:20 pm
I know the result can be determined by some sort of binary combination of the two numbers but I can't remember which.
(A or B) xor 3 or equivalently 3-(A or B)
Wait so even if both calculators input the same number to Port (0 and 0 say), they would each read the inverse of that number (3) ?  That's weird D:

Quote from: Darl181 on January 08, 2012, 03:19:15 pm
With Z-Select, does it Goto the label or does it run it as a subroutine?
It Goto's the Label
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Offline Happybobjr

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Re: Axe Q&A
« Reply #1295 on: January 08, 2012, 10:29:55 pm »
That sounds useful!
what do you mean the inverse?
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Offline Builderboy

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Re: Axe Q&A
« Reply #1296 on: January 08, 2012, 10:45:29 pm »
Binary inverse, as in all the bits get flipped.  The result read depends on how Axe treats the output of the Port, as well as how the Ports interact.  I was under the impression there was some sort of logical equation, but I also thought that if both calcs agreed on an output number, the input read would be equal to that number.
« Last Edit: January 08, 2012, 10:46:35 pm by Builderboy »
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Offline parserp

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Re: Axe Q&A
« Reply #1297 on: January 09, 2012, 08:09:55 pm »
Do you have to do something special to write to a GDB?
I tried using this one line in my code and I got an ERR:UNDEFINED

Copy(L1,GDB1,768)
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Offline Builderboy

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Re: Axe Q&A
« Reply #1298 on: January 09, 2012, 08:45:32 pm »
You don't need to do anything special (unless you are writing an app, in which case it won't work) but you need to have GDB1 defined already.  Do you?
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Offline Yeong

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Re: Axe Q&A
« Reply #1299 on: January 09, 2012, 08:49:32 pm »
I thought L1 was smaller than 768 bytes?
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Offline epic7

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Re: Axe Q&A
« Reply #1300 on: January 09, 2012, 08:50:31 pm »
L1 is 714 bytes says the axe commands list.
« Last Edit: January 09, 2012, 08:55:01 pm by epic7 »
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Offline ztrumpet

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Re: Axe Q&A
« Reply #1301 on: January 09, 2012, 09:07:30 pm »
Quote from: TBO_Yeong on January 09, 2012, 08:49:32 pm
I thought L1 was smaller than 768 bytes?
If you first Realloc the variables it makes L1 768 bytes.  Perhaps he did that.
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Offline chattahippie

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Re: Axe Q&A
« Reply #1302 on: January 09, 2012, 10:12:33 pm »
Quote from: parser padwan on January 08, 2012, 01:09:23 am
Quote from: Darl181 on January 08, 2012, 01:07:27 am
No, Text() can only write to L6.  It's hard-coded into the routine.
Dang. I'll have to do some tricky buffer copying. :)

DispGraph(L3, L6)r should work unless Axe doesn't allow the buffers to be switched
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Offline Darl181

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Re: Axe Q&A
« Reply #1303 on: January 09, 2012, 10:14:38 pm »
That should work.
The only other way I can think of is to have l6 blank, write the text, and copy the buffer to L3 or something.
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Offline parserp

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Re: Axe Q&A
« Reply #1304 on: January 09, 2012, 10:34:05 pm »
Quote from: Builderboy on January 09, 2012, 08:45:32 pm
You don't need to do anything special (unless you are writing an app, in which case it won't work) but you need to have GDB1 defined already.  Do you?
I don't think so, what do I have to do to make it defined?
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