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Why does sin(1) return 3 and sin(3) return 11?
..C=2 or or(C=6)?0→E,1→E{C+GDB0BA}→A // Suspecting this line..!If (getKey(30)+(getKey(31))+(getKey(32))+(getKey(38))+(getKey(40))+(getKey(46))+(getKey(47))+(getKey(48))-1)U*10+Bul→r1{C+GDB0BQ}→QE*8+X→{r1}r.X+(8*(C!=2))->{r1}^^rE*8+Y→{r1+2}r.Y+(8*(C!=2))->{r1+2}^^r // ...or thesegetKey(32)*2+(getKey(30)*2)-(getKey(48)*2)-(getKey(46)*2)+(getKey(31)*3)-(getKey(47)*3)→F*A→{r1+4}rgetKey(30)*2+(getKey(46)*2)-(getKey(32)*2)-(getKey(48)*2)+(getKey(38)*3)-(getKey(40)*3)→G*A→{r1+6}rIf OptIf {Opt}!If (C=1)+(C=5)rand^3-1*8+{r1}r→{r1}rrand^3-1*8+{r1+2}r→{r1+2}r.SWITCHED^F*4+{r1+4}r→{r1+4}rG*4+{r1+6}r→{r1+6}rEndElseC!=1*S+{r1+4}r+(rand^3)-1→{r1+4}rC!=1*T+{r1+6}r+(rand^3)-1→{r1+6}rEndEndC→{r1+8}{C+GDB0XP}→{r1+9}!If C-6F*9+{r1}r→{r1}rG*9+{r1+2}r→{r1+2}rEnd!If C-1{r1+4}r*6+{r1}r→{r1}r{r1+6}r*6+{r1+2}r→{r1+2}rEndU++End