Author Topic: Axe Q&A (Read 600865 times)

Hayleia · « **Reply #600 on:** August 19, 2011, 12:16:39 pm »

Spoiler For false:

I also have a question. How do we handle 2 bytes data

?
(Axe 0.5.3 user)
To have 65535 and 65535 at GDB1 and GDB1+1, do I do
Data(65535^r,65535^r)→GDB1
or Data(65535,65535)^r→GDB1
or Data(255^r,255^r,255^r,255^r)→GDB1
etc...
and to read, I use {GDB1^r} or {GDB1}^r ?

Stefan Bauwens · « **Reply #601 on:** August 19, 2011, 12:26:58 pm »

Quote from: Hayleia on August 19, 2011, 12:16:39 pm

Quote from: Stefan Bauwens on August 18, 2011, 12:10:34 pm
So If I didn't make a mistake here, this should draw (a part of the map) to fill the screen?
Code: [Select]
.0 [hexcode1]->pic0 .1 [hexcode2] for a,0,11 for b,0,7 pt-on(a*8-8,b*8-8,{Y*Width+X+pointer}+pic0) end endThanks a lot Final Ti.

Nope, better like this (In black, your correct code. In red, your wrong code. In green, corrected code,)
.0 [hexcode1]->Pic0 .1 [hexcode2] for a,0,11 for b,0,7 For(A,0,11 For(B,0,7 .not really an error but not written with the exact syntax pt-on(a*8-8,b*8-8,{Y*Width+X+pointer}+pic0) Pt-On(A*8,B*8,{Y*Width+X+Pic0} .you put +pointer but the pointer is Pic0 here End End

Thanks for correcting me. But if my map dat is stored in GDB1 then shouldn't I write: pt-on(a*8-8,b*8-8,{Y*Width+X+GDB1}+pic0)
That's the only place I put GDB1, so I think it has to be there or else it can't read it.

FinaleTI · « **Reply #602 on:** August 19, 2011, 12:27:12 pm »

Quote from: Hayleia on August 19, 2011, 12:16:39 pm

pt-on(a*8-8,b*8-8,{Y*Width+X+pointer}+pic0)
Pt-On(A*8,B*8,{Y*Width+X+Pic0} .you put +pointer but the pointer is Pic0 here

Actually, that's not correct either. That would read the data from the tile data, not the map data, which is what pointer represented.
The correct way would actually be:

Code: [Select]

Pt-On(A*8,B*8,{Y*Width+X+pointer} * 8 + Pic0)Because each tile is 8 bytes.

And a tip to Stefan Bauwens: Always close your parenthesis in Axe, because it doesn't result in more optimized code, and can cause compilation problems if you don't.

Hayleia · « **Reply #603 on:** August 19, 2011, 12:31:15 pm »

(°-.-) sorry, I did not read properly. I put in a spoiler so people don't get wrong by reading me.
(lol I got wrong even if I made a game based on tilemapping

)

Stefan Bauwens · « **Reply #604 on:** August 19, 2011, 12:38:14 pm »

Thanks both for the help. I just want to be sure of something so I ask this question:

Code: [Select]

[010101010101]->GDB1So "01" is 8 bytes?

Hayleia · « **Reply #605 on:** August 19, 2011, 12:38:36 pm »

"01" is 1 byte=8 bits (hope I am not wrong on that one)

Quote from: FinaleTI on August 19, 2011, 12:27:12 pm

Because each tile is 8 bytes.

...is referring to the sprites: [hexcode]→Pic0

Stefan Bauwens · « **Reply #606 on:** August 19, 2011, 12:45:26 pm »

But GDB1+8 will read only 2 digits?

Hayleia · « **Reply #607 on:** August 19, 2011, 12:47:10 pm »

No, it is an hex code. [01]=b00000001

Stefan Bauwens · « **Reply #608 on:** August 19, 2011, 12:48:37 pm »

Quote from: Hayleia on August 19, 2011, 12:47:10 pm

No, it is an hex code. [01]=b00000001

But if "01" is one tile and my map reader has to read each tile seperate, how does he only read that one?

Hayleia · « **Reply #609 on:** August 19, 2011, 12:50:37 pm »

um.. I am not English so the word digit is a bit lolwut for me.
The map reader, in [01] understand the number 1, and by [FF] understands 255 if that helps.

Stefan Bauwens · « **Reply #610 on:** August 19, 2011, 12:51:20 pm »

Ok, thanks.

Hayleia · « **Reply #611 on:** August 19, 2011, 12:54:50 pm »

No problem. I help those who need help because I first received help when I needed.
Yay, quoting myself

Quote from: Hayleia on August 19, 2011, 12:16:39 pm

I also have a question. How do we handle 2 bytes data ?
(Axe 0.5.3 user)
To have 65535 and 65535 at GDB1 and GDB1+1, do I do
Data(65535^r,65535^r)→GDB1
or Data(65535,65535)^r→GDB1
or Data(255^r,255^r,255^r,255^r)→GDB1
etc...
and to read, I use {GDB1^r} or {GDB1}^r ?

FinaleTI · « **Reply #612 on:** August 19, 2011, 01:13:33 pm »

Quote from: Hayleia on August 19, 2011, 12:54:50 pm

No problem. I help those who need help because I first received help when I needed.
Yay, quoting myself
Quote from: Hayleia on August 19, 2011, 12:16:39 pm
I also have a question. How do we handle 2 bytes data ?
(Axe 0.5.3 user)
To have 65535 and 65535 at GDB1 and GDB1+1, do I do
Data(65535^r,65535^r)→GDB1
or Data(65535,65535)^r→GDB1
or Data(255^r,255^r,255^r,255^r)→GDB1
etc...
and to read, I use {GDB1^r} or {GDB1}^r ?

Data(65535^r,65535^r)→GDB1
Is the correct way of storing 65535 and 65535 to GDB1 and GDB1+2.

You would access each number like {GDB1}^r, {GDB1+2}^r, etc., but you must remember that since you're dealing with 2 byte numbers, the addresses are two bytes apart.
Reading {GDB1}^r and {GDB1+1}^r is incorrect because while you read the first number correctly, you're reading a byte from the first and second number for your {GDB1+1}^r statement, resulting in an incorrect number.

Hayleia · « **Reply #613 on:** August 20, 2011, 02:26:13 am »

Ok, thanks a lot

Happybobjr · « **Reply #614 on:** August 22, 2011, 06:07:39 pm »

could someone please provide me a code to check if another program is using the same code

poorly said

Like to make sure, in a 2 player game, that the other person is running the program to.

Author Topic: Axe Q&A (Read 600865 times)

Hayleia

Re: Axe Q&A

Stefan Bauwens

Re: Axe Q&A

FinaleTI

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Hayleia

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Stefan Bauwens

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Hayleia

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Stefan Bauwens

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Hayleia

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Stefan Bauwens

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Hayleia

Re: Axe Q&A

Stefan Bauwens

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Hayleia

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FinaleTI

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Hayleia

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Happybobjr

Re: Axe Q&A