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Author Topic: Axe Q&A  (Read 591065 times)

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Offline Darl181

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Re: Axe Q&A
« Reply #75 on: February 18, 2011, 08:35:35 pm »
Question dealing with earlier: the tilemapper I'm making reads from the RAM at random (like, rand→A at the beginning and for the rest of the program it reads from {A}).
Does this mean the width is variable?
If not what would the width be?  I'm thinking 256, but I'm not sure...
« Last Edit: February 18, 2011, 08:36:08 pm by Darl181 »
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #76 on: February 18, 2011, 08:36:18 pm »
Depends on how you're storing the width?
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Offline Darl181

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Re: Axe Q&A
« Reply #77 on: February 18, 2011, 08:42:03 pm »
For this:
Spoiler For optimized:
Quote from: Runer112 on February 18, 2011, 05:22:09 pm
Here's the most optimized code I could come up with. Only while finding the top left corner does it fully calculate the position. The other corners reuse previously found values and conditionally add to them as necessary. Note that this will only work with the corner locations being calculated in the order below (although code can exist between calculations), and only for the player being at (45,29) due to optimizations tuned specifically to this coordinate.


Code: [Select]
.Top Left
29-Osub(D8)+J*[map_width]+(45-Nsub(D8)+I)+E→r₆
.Top Right
Nsub(O00)→r₅+r₆
.Bottom Left
Osub(O00)*[map_width]+r₆→r₆
.Bottom Right
r₅+r₆

Lbl D8
  /2/2/2
Return

Lbl O00
  //2≠⁻2
Return
Spoiler For unoptimized:
Quote from: Runer112 on February 18, 2011, 07:05:44 pm
This is effectively what it does, only this is larger and slower.

Code: [Select]
.Top Left
29-O/2/2/2+J*[map_width]+(45-N/2/2/2+I)+E
.Top Right
29-O/2/2/2+J*[map_width]+(51-N/2/2/2+I)+E
.Bottom Left
35-O/2/2/2+J*[map_width]+(45-N/2/2/2+I)+E
.Bottom Right
35-O/2/2/2+J*[map_width]+(51-N/2/2/2+I)+E

Also wow, this topic grew fast...
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #78 on: February 18, 2011, 08:51:51 pm »
Please don't put [code] tags in spoilers. It's tiny in Chrome :(
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Offline Darl181

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Re: Axe Q&A
« Reply #79 on: February 18, 2011, 08:53:37 pm »
Oh.. :P
Quote from: Darl181 on February 18, 2011, 08:42:03 pm
For this:
Quote from: Runer112 on February 18, 2011, 05:22:09 pm
Here's the most optimized code I could come up with. Only while finding the top left corner does it fully calculate the position. The other corners reuse previously found values and conditionally add to them as necessary. Note that this will only work with the corner locations being calculated in the order below (although code can exist between calculations), and only for the player being at (45,29) due to optimizations tuned specifically to this coordinate.


Code: [Select]
.Top Left
29-Osub(D8)+J*[map_width]+(45-Nsub(D8)+I)+E→r₆
.Top Right
Nsub(O00)→r₅+r₆
.Bottom Left
Osub(O00)*[map_width]+r₆→r₆
.Bottom Right
r₅+r₆

Lbl D8
  /2/2/2
Return

Lbl O00
  //2≠⁻2
Return
Quote from: Runer112 on February 18, 2011, 07:05:44 pm
This is effectively what it does, only this is larger and slower.

Code: [Select]
.Top Left
29-O/2/2/2+J*[map_width]+(45-N/2/2/2+I)+E
.Top Right
29-O/2/2/2+J*[map_width]+(51-N/2/2/2+I)+E
.Bottom Left
35-O/2/2/2+J*[map_width]+(45-N/2/2/2+I)+E
.Bottom Right
35-O/2/2/2+J*[map_width]+(51-N/2/2/2+I)+E

Also wow, this topic grew fast...
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Offline Darl181

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Re: Axe Q&A
« Reply #80 on: February 19, 2011, 04:42:46 am »
Okay, I kind of have the above figured out.
I'm thinking of making my old character explorer thing (here) more useful for two-byte tokens.
One idea is to text the token to the graphscreen.
Does the graphscreen do text wrapping, and if not, is there a way to make it?
« Last Edit: February 19, 2011, 04:42:58 am by Darl181 »
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Offline aeTIos

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Re: Axe Q&A
« Reply #81 on: February 19, 2011, 09:39:39 am »
How does the float{} function work? I've tried it, but everything after float{X} returned an error...
« Last Edit: February 19, 2011, 09:39:55 am by aeTIos »
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Offline Happybobjr

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Re: Axe Q&A
« Reply #82 on: February 19, 2011, 10:33:22 am »
your x has to be a location in the memory.
Such as L1
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #83 on: February 19, 2011, 10:56:11 am »
Quote from: aeTIos on February 19, 2011, 09:39:39 am
How does the float{} function work? I've tried it, but everything after float{X} returned an error...

Floating values are always nine bytes. It should be stored somewhere in RAM (such as after doing something like GetCalc("varA")→P). Then float{P} returns the value of the nine bytes pointed to (hence the curly braces after float{).
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Offline Darl181

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Re: Axe Q&A
« Reply #84 on: February 20, 2011, 01:40:21 am »
Is there a way to make RecallPic and StorePic work in a way so they don't overwrite the buffer being stored to?  So, instead of it working like Pt-Off, it would work like pt-on or pt-change?
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Offline Builderboy

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Re: Axe Q&A
« Reply #85 on: February 20, 2011, 01:42:24 am »
You could do something like this:

Code: [Select]
For(F,0,767
{L3+F} or {L6+F}->{L6+F}
End
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Offline Darl181

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Re: Axe Q&A
« Reply #86 on: February 20, 2011, 02:16:38 am »
I thought the buffers were in bits though...that would work anyway?
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Offline Builderboy

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Re: Axe Q&A
« Reply #87 on: February 20, 2011, 02:17:17 am »
yep, OR works with the bits for us :)
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Offline Darl181

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Re: Axe Q&A
« Reply #88 on: February 20, 2011, 02:19:14 am »
Ah cool.
So that does xor, or is it like Pt-on?
« Last Edit: February 20, 2011, 02:19:23 am by Darl181 »
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #89 on: February 20, 2011, 10:51:36 am »
Pt-On is OR, Pt-Change is XOR.

Pt-Off is really a mask, hence why it's so much bigger.
« Last Edit: February 20, 2011, 10:51:54 am by Deep Thought »
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