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Author Topic: Axe Q&A  (Read 591383 times)

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Offline Munchor

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Re: Axe Q&A
« Reply #240 on: April 25, 2011, 06:04:10 am »
Thanks calc84maniac and Michael Lee :) I found another way of doing it though.

I have a new question... How to handle 2 byte highscores with appvars?

I just need to store 1 value in the appvar, but it is over 255.

I have the appvar created with 2 bytes of size, they are all I need.

I tried 500->{T+1} and 500->{T} and then to display it tried Text(X,Y,{T}>Dec and Text(X,Y,{T+1}>Dec.

What should I do?
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Offline Binder News

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Re: Axe Q&A
« Reply #241 on: April 25, 2011, 06:40:33 am »
add an r at the end of the {}s
500->{T}r
Text(X,Y,{T}r>Dec
« Last Edit: April 25, 2011, 06:42:27 am by Binder News »
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Offline Munchor

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Re: Axe Q&A
« Reply #242 on: April 25, 2011, 06:42:54 am »
Thx binder, graduados gás already told me thogh. Thx :)
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Offline Binder News

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Re: Axe Q&A
« Reply #243 on: April 25, 2011, 06:43:18 am »
Welcome :)
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Offline Munchor

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Re: Axe Q&A
« Reply #244 on: April 28, 2011, 09:31:38 am »
I have a new question :$

How to check if a number in a variable is divisible by another number.

Let's say I have the var B and want to check if it is divisible by 5. Axe is an integer language, so can that be done?
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Offline Freyaday

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Re: Axe Q&A
« Reply #245 on: April 28, 2011, 09:35:49 am »
!If A^B
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #246 on: April 28, 2011, 09:49:44 am »
Yep, remember ^ (modulus) is just the remainder after division, so if it's zero, there is no remainder (it's divisible).
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Offline Munchor

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Re: Axe Q&A
« Reply #247 on: April 28, 2011, 09:55:42 am »
Quote from: Deep Thought on April 28, 2011, 09:49:44 am
Yep, remember ^ (modulus) is just the remainder after division, so if it's zero, there is no remainder (it's divisible).

I had no idea there was such an operator. Thanks :D
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Offline Munchor

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Re: Axe Q&A
« Reply #248 on: April 29, 2011, 02:16:02 pm »
I have a new question:

Code: [Select]
:If X=88 or (Y=62 or (X=65532 or (pxl-Test(X-1,Y+2 or (pxl-Test(X-1,Y+3 or (pxl-Test(X-1,Y+4 or (pxl-Test(X,Y+1 or (pxl-Test(X,Y+5 or (pxl-Test(X+1,Y+1 or (pxl-Test(X+1,Y+6 or (pxl-Test(X+2,Y or (pxl-Test(X+2,Y+7 or (pxl-Test(X+3,Y+8 or (pxl-Test(X+4,Y-1 or pxl-Test(X+4,Y+8 or (pxl-Test(X+5,Y or (pxl-Test(X+5,Y+8 or (pxl-Test(X+6,Y or (pxl-Test(X+6,Y+8 or (pxl-Test(X+7,Y+8 or (pxl-Test(X+8,Y or (pxl-Test(X+8,Y+3 or (pxl-Test(X+8,Y+4 or (pxl-Test(X+8,Y+5 or (pxl-Test(X+8,Y+7
First of all, does this error have any problem? It doesn't seem to be working as I want it to. Is there a problem with parentheses or having too many pxl-Test.

Code: [Select]
:If X=88 or (Y=62 or (X=65533 or (pxl-Test(X+8,Y) or (pxl-Test(X+8,Y+7 or (pxl-Test(X+6,Y+1 or (pxl-Test(X+2,Y or (pxl-Test(X+7,Y+8 or (pxl-Test(X+7,Y-1 or (pxl-Test(X+2,Y+7 or (pxl-Test(X+3,Y+8 or (pxl-Test(X+4,Y+8 or (pxl-Test(X,Y+3
This works more or less.

Thanks, any help is appreciated.
« Last Edit: April 29, 2011, 02:16:26 pm by Scout »
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Offline aeTIos

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Re: Axe Q&A
« Reply #249 on: April 29, 2011, 02:20:11 pm »
You should write a for loop for the pxl-test.
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Offline Munchor

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Re: Axe Q&A
« Reply #250 on: April 29, 2011, 02:20:52 pm »
Quote from: aeTIos on April 29, 2011, 02:20:11 pm
You should write a for loop for the pxl-test.

That's actually a very good idea, I never thought of it. Thanks.
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Offline aeTIos

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Re: Axe Q&A
« Reply #251 on: April 29, 2011, 02:22:43 pm »
You should do it this way:
Code: [Select]
0->Z
For(A,0,7
Z+Pxl-Test(X,Y+A)->Z
End
If Z!=0
blah blah
end
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Offline Munchor

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Re: Axe Q&A
« Reply #252 on: April 29, 2011, 02:26:46 pm »
Code: [Select]
:If X=88 or (Y=62 or (X=65532 or (pxl-Test(X-1,Y+2 or (pxl-Test(X-1,Y+3 or (pxl-Test(X-1,Y+4 or (pxl-Test(X,Y+1 or (pxl-Test(X,Y+5 or (pxl-Test(X+1,Y+1 or (pxl-Test(X+1,Y+6 or (pxl-Test(X+2,Y or (pxl-Test(X+2,Y+7 or (pxl-Test(X+3,Y+8 or (pxl-Test(X+4,Y-1 or pxl-Test(X+4,Y+8 or (pxl-Test(X+5,Y or (pxl-Test(X+5,Y+8 or (pxl-Test(X+6,Y or (pxl-Test(X+6,Y+8 or (pxl-Test(X+7,Y+8 or (pxl-Test(X+8,Y or (pxl-Test(X+8,Y+3 or (pxl-Test(X+8,Y+4 or (pxl-Test(X+8,Y+5 or (pxl-Test(X+8,Y+7


I have that image (click and enlarge to view the pixels). The code above is supposed to make a pixel collision for copter. any ideas?

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Offline aeTIos

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Re: Axe Q&A
« Reply #253 on: April 29, 2011, 02:28:17 pm »
Do it the way I posted. this is a cheap, but good way for collission checking.
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Offline Runer112

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Re: Axe Q&A
« Reply #254 on: April 29, 2011, 03:11:15 pm »
Here is a pretty small method for pixel-based sprite collision checking. Whereas your previous combination of 22 hard-coded pxl-Test() checks weighs in at a whopping 620 bytes, this routine is 99 bytes. As you might expect from this loop-based approach, though, it trades size for speed. Whereas your previous method would take about 9,000 cycles, this method will take about 26,000 cycles for your sprite.

Another great thing about this approach is that it, instead of using a large list of X and Y offsets for each pixel that you want to check, it simply reads from a sprite. This means that this routine can be adapted to any sprite by simply changing the Pic0 reference to point to your 8x8 sprite. However, this also means that is slowed down additionally by checking pixels inside of the sprite, which you may not need to check. You can get rid of these unnecessary checks by having this routine read from an 8x8 sprite only containing the collision points (probably the border). If you added another 8x8 sprite containing the 22 collision points you used in your hardcoded method, you would be adding 8 bytes for the sprite but subtracting about 6,000 cycles from the collision checking.

Code: (99 bytes, ~26,000 cycles if no collision (based on Scout's helicopter sprite)) [Select]
8
While 1
  -1→T    .that's a subtraction sign
  {+Pic0}→U
  8
  While 1
    -1→S
    If U^2
      If pxl-Test(X+S,Y+T)
        Goto COL
      End
    End
    U/2→U
  End!If S
End!If T
« Last Edit: April 29, 2011, 03:29:41 pm by Runer112 »
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