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Author Topic: Axe Q&A  (Read 588008 times)

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Offline Aichi

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Re: Axe Q&A
« Reply #435 on: June 01, 2011, 08:12:01 am »
Take a look at the added video in my last post. The Axe Parser hooks have to be enabled.
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Offline Aichi

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Re: Axe Q&A
« Reply #436 on: June 04, 2011, 01:24:40 pm »
Are there any optimizations for these routines?

Collision check routine for an object at r1, r2 and an object at r3, r4:
Code: [Select]
Lbl O
< (r2+6) and (r1+6 > r3 and (r3+6 > r1 and (r4+6 > r2
Return
Changing a tile (arg1 = X, arg2 = Y, HL = new tile ID):
Code: [Select]
Lbl W
-> {r2 + 4 / 8 * 60 + (r1 + V + 4 / 8) + L3 + J }
Return
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #437 on: June 04, 2011, 01:32:31 pm »
Code: (Axe) [Select]
Lbl O
-r₂+5<11 and (r₁-r₃+5<11)
Return
Working on the second.

EDIT: All I can get there is to swap the J and L₃, like this:

Code: (Axe) [Select]
Lbl W
→{r₂+4/8*60+(r₁+V+4/8)+J+L₃}
Return
You should always put constants last in an expression. It actually makes a difference (in both speed and size).
« Last Edit: June 04, 2011, 01:36:05 pm by Deep Thought »
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Offline Aichi

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Re: Axe Q&A
« Reply #438 on: June 04, 2011, 02:01:07 pm »
Wow, thanks a lot, Deep Thought. :O
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Offline Deep Toaster

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Re: Axe Q&A
« Reply #439 on: June 04, 2011, 03:05:10 pm »
Np. Make sure you test it first, because I haven't ;D

Should work though.
« Last Edit: June 04, 2011, 03:05:23 pm by Deep Thought »
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Offline Runer112

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Re: Axe Q&A
« Reply #440 on: June 04, 2011, 05:28:35 pm »
Very good, padawan Deep Thought. But you still have much to learn to become a jedi master. ;)

10 bytes saved
Code: [Select]
Lbl O
Return!If -r₂sub(O0)
r₃-r₁
Lbl O0
+5<11
Return

3 bytes and ~1250 cycles saved  —  Note: although putting constants last is a good practice, in this case it saved nothing
Code: [Select]
Lbl W
→{r₂sub(W0)*60+(r₁+Vsub(W0))+J+L₃}
Lbl W0
*64+256/512
Return
« Last Edit: June 04, 2011, 05:43:09 pm by Runer112 »
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Offline Aichi

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Re: Axe Q&A
« Reply #441 on: June 04, 2011, 06:03:24 pm »
 O.O
That's epic, Runer. I would have never be able to come up with those things.
Does your collision routine affect the speed as well? Speed has more priority than size for me, at least in these cases.
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Offline Runer112

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Re: Axe Q&A
« Reply #442 on: June 04, 2011, 07:24:09 pm »
The collision routine will be 7 cycles slower if the y values are in the collision range, but it will be 115 cycles faster if they are not.

Also, if you're aiming for speed, you may want to use this instead of what I originally suggested for the second routine. Optimizing for size and optimizing for speed are two different beasts altogether!

Compared to my size-optimized suggestion: 8 bytes larger, ~1200 cycles faster
Code: [Select]
Lbl W
→{r₂sub(W0)*10*6+(r₁+Vsub(W0))+J+L₃}
Return
Lbl W0
/2/2+1/2
Return
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Offline Aichi

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Re: Axe Q&A
« Reply #443 on: June 05, 2011, 02:28:24 pm »
Axe does automatically round off numbers by dividings. That causes a difference between X + 4 / 8 and X / 2 / 2 + 1 / 2.
* 64 + 256 / 512 seems fine though, thanks. :)
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Offline ztrumpet

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Re: Axe Q&A
« Reply #444 on: June 05, 2011, 04:30:26 pm »
Quote from: Aichi on June 05, 2011, 02:28:24 pm
Axe does automatically round off numbers by dividings. That causes a difference between X + 4 / 8 and X / 2 / 2 + 1 / 2.
* 64 + 256 / 512 seems fine though, thanks. :)
I don't think there should be a difference between the three.  Are you sure that there was one?
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Offline calc84maniac

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Re: Axe Q&A
« Reply #445 on: June 05, 2011, 04:30:38 pm »
Quote from: Aichi on June 05, 2011, 02:28:24 pm
Axe does automatically round off numbers by dividings. That causes a difference between X + 4 / 8 and X / 2 / 2 + 1 / 2.
* 64 + 256 / 512 seems fine though, thanks. :)
Well, X+4/4 is the same as X/2/2+1 though.
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Offline Aichi

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Re: Axe Q&A
« Reply #446 on: June 05, 2011, 05:21:48 pm »
Hm, strange, I've tested this:

Code: [Select]
.T
ClrHome
For(F,0,500)
If (Fsub(A)) - (Fsub(B))
Output(0,,F>Dec
End
End
sub(A)
+4 / 8
Return
sub(B)
/2/2+1/2
Return

And the screen stays white, so /2/2+1/2 is really equal to +4 / 8 for Axe Parser,
but /2/2+1/2 continues being not working (that seems to sound terribly for people who can actually speak correct english :P) in the code of my real project. It seems that any section of my code affects the collision routine.
I will use * 64 + 256 / 512, that works fine. :)
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Offline Darl181

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Re: Axe Q&A
« Reply #447 on: June 05, 2011, 05:26:41 pm »
Under what conditions does...
Code: [Select]
If inData(A,Data([num here],[another num],[etc],0))...return as true?

I made a little test program and it works fine, but when I put it into the source for Shift--taking out If D=2 or (D=3) and replacing it with If inData(D,Data(2,3,0))--it seems to always output true, even when I explicitly do 5→D immediately before ???
« Last Edit: June 05, 2011, 05:32:17 pm by Darl181 »
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Ashbad

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Re: Axe Q&A
« Reply #448 on: June 05, 2011, 05:28:55 pm »
Quote from: Darl181 on June 05, 2011, 05:26:41 pm
Under what conditions does...
Code: [Select]
If inData(A,Data([num here],[another num],[etc],0))...return as true?

I made a little test program and it works fine, but when I put it into the source for Shift--taking out If D=2 or (D=3) and replacing it with If inData(D,(2,3,0))--it seems to always output true ???

You need to do:

Code: [Select]
inData(D,Data(2,3,0))
It'll take the Data() in and check if anything in it is equal to D.  Always put 0 at the end, also. :)
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Offline Darl181

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Re: Axe Q&A
« Reply #449 on: June 05, 2011, 05:32:04 pm »
I know, look at the code box just above it :P
Forgot to type that in, but what I did was practically copy/paste from the working version and changed the numbers.  And it didn't work.
« Last Edit: June 05, 2011, 05:32:31 pm by Darl181 »
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