I'm pretty sure it's like that, just have the second line of hex under/part of the first one.

...
Ok, I was optimizing last night and wrote down a bunch of Q's as I went.

Do the ?/?? conditionals save space in the executable in relation to conventional If loops?  How about speed?

Can they be nested?  like B?(A++5?-1→A),→A works, nvm that

Which is faster: If (commonly true) / If (sparsely true) ?

So it's optimized to put the constants at the end...what if it's like L2+2?  Would a different order influence anything?

1. ? and ?? are just convenience notation, so they are probably the same as If statements.
2. The speed of an If statement depends on what conditionals you use. However, for If / Else statements, the Else is generally faster due to one fewer jump. This is why I generally put the commonly true branch in the else part.
3. L₂+2 and 2+L₂ both optimize to 35388

If you mean something like external levels, you could create a new appvar then copy to it.
Say you have the stuff to be stored to the appvar in L1:
"appvNAME"→Str1
GetCalc(Str1,768)→P
Copy(L1,P,768)
and now you have an external appvar that has the contents of whatever was in L1

How do I put parts of a code as an appvar?

This is extremely difficult to get working, because of the way assembly works.  Assembly code only works at a specific location, if it is moved to anywhere else in memory, it will cause horrible crashes.  The issue with running code in an appvar, is that you need to copy that code to $959D, which is where your current program is!  It becomes a bit easier if your current program is an appvar, but even then it requires custom asm and Bcall knowledge.  I am not an expert on getting it to work, so I can't provide the details.  So the most I can say is try to fit all your code in 1 program, and use a program like Fullrene or Crabcake to surpass the execution limits. 

Problem that's had me stuck for a few days:

I honestly cant find what's wrong with it

The beginning part that works.
Where it starts to not work
:If (getKey(54))∗((H=0)+(H>40))∗(B=0) ;works
:If Y∕256=48 ;works
:1➔H
:Else
:2➔H
:End
:End
:If H=1 ;works
:Y−256➔Y
:If Y∕256=26
:2➔H
:End
:End
:If H=2
:X∕256➔S
:Y∕256➔T
:R➔θ
:Repeat pxl-Test(S,T) ;all this works
:T++
:If θ
:S++
:Else
:S−−
:End
:End
:If H>1
:If H≤40
:1➔P ;works
:Line(X∕256+7,Y∕256,S,T) ;this flashes on, but just once, so doesn't work much
:Else
:0➔P
:End
:If H<15
:Y+256➔Y ;doesnt work
:If θ
:X+256➔X ;but this does (1 time)
:Else
:X−256➔X
:End
:H++ ;i think this only works once.
:If Y∕256=48
:0➔H➔P➔S➔T
:10➔B
:End
:EndI cant tell if this part works or not.
Then just
:Pt-On(X∕256,Y∕256,P∗8+Pic1)
:If B
:B−−
:End
:DispGraph
:End(which works)

Good idea

In the middle section, the guy jumps into the air and freezes. I believe that H gets stuck at 3 even though I have an H++.
At the line,
:1➔P ;works
:Line(X∕256+7,Y∕256,S,T) ;but this only flashes on for 1 frame!

The guy is supposed to move, here
By the time it gets here, H is succesfuly at 2, so it works
(If H>1 is also here)

:If H<15
:Y+256➔Y ;doesnt work
:If θ
:X+256➔X ;but this does, but only 1 time for some reason
:Else
:X−256➔X
:End
:H++ ;This H++ only works once, to get H to 3. Its supposed to take it up to 15, though.
:If Y∕256=48 ;This is if the guy hits the ground early, but not really important right now.
:0➔H➔P➔S➔T
:10➔B
:End
:End

Afterwards, there is

:If H≥15 and (H≤25)

But I obviously cant get that to work since H gets stuck at 3
I don't know if there is something preventing it from changing

I tried exactly that

I can't get to a computer right now, so I'll have to upload the calc file Tommorow. However, the full code is posted above.

Try removing your text?