0 Members and 2 Guests are viewing this topic.
:.M is the level # you are on:If M:0->T+768->U:Else:(((M-1)768)+1)->T+767->U //<------this is the only part screwing up. U gets stored fine (I think), but T is being weird.:End:0->C:For(r6,T,U:{Y0+r6}->{L3+C}:C++:End
Try putting a * in therechange (M-1)768to(M-1)*768Hope that helps
[0000000000000]->GDB1[0000000000000][0000000000000][0000000000000][0000000000000][0000000000000][0000000000000][0000000000000]
[0000000000000]->GDB1for(A,0,6)[0000000000000]end
You can also do Buff(64)→GDB1 and it'll have the same result as the first one (if you want it to be all zeroes)
Quote from: Darl181 on November 30, 2011, 11:40:15 amYou can also do Buff(64)→GDB1 and it'll have the same result as the first one (if you want it to be all zeroes)With this method, will the data be stored in the program or in some free ram ?
PROGRAM:A:.HISCORE:"appvMyScore"→Str1:GetCalc(Str1,Y1)→A:Return!If A:Disp {Y1}rGetCalc does NOT return apointer when opening a file.Its simply non-zero if itexists in archive and 0otherwise.