Author Topic: Axe Q&A (Read 587484 times)

josh landers · « **Reply #1725 on:** April 22, 2014, 12:47:22 pm »

Edit: removed quote.
The C9 is what is getting you...

Code: [Select]

:Asm(FDCB249EC9)You should be able to get it to work if you remove the C9

NikProgrammer · « **Reply #1726 on:** April 22, 2014, 12:50:49 pm »

Ok thanks... I cannot hex, I learned this from YouTube, I supose C9 Stops the program?

josh landers · « **Reply #1727 on:** April 22, 2014, 12:54:03 pm »

Ask Xeda, she knows quite a bit about the opt-codes.

TheMachine02 · « **Reply #1728 on:** April 22, 2014, 12:57:40 pm »

C9 is the equivalent of the assembly "ret" command, wich is the equivalent of the axe command "return".
It indeed stop the program and give the control back to the OS if it is not use in a routine or such.

aeTIos · « **Reply #1729 on:** April 22, 2014, 01:02:28 pm »

However, your program should be doing what it should do. It only won't give you feedback.

Sorunome · « **Reply #1730 on:** April 22, 2014, 01:52:46 pm »

Ugh, i got a little problem with axes Copy().
I have the following (relevant hex in bold):
Copy([2D0100001D2D1D000A00],L5,10)

And right after that, when i check the value of {L5+7}^r it is 2560.

Any clue what is going on here?

aeTIos · « **Reply #1731 on:** April 22, 2014, 01:55:38 pm »

Yup. Little endian going on. You need to reverse the bits.

Sorunome · « **Reply #1732 on:** April 22, 2014, 02:05:46 pm »

Yup, that was it, thanks a lot!

Hayleia · « **Reply #1733 on:** April 22, 2014, 02:10:41 pm »

Quote from: aeTIos on April 22, 2014, 01:55:38 pm

Yup. Little endian going on. You need to reverse the bits.

*bytes. You don't have to reverse everything, just the two bytes

NikProgrammer · « **Reply #1734 on:** April 22, 2014, 02:14:40 pm »

Maybe I need some more information about pointers. If I type in: [BlaBla hex]->Pic 1 and then Pt-on(x,y,Pic 1+Z, what will happen then?

Sorunome · « **Reply #1735 on:** April 22, 2014, 02:16:31 pm »

A pointer is a number that points to some location in RAM.
With [hex]->Pic1 you create a pointer, Pic1, that points to the location in ram where that hex is stored.
So Pic1 can be treated just like a number.
Let's say you want the second byte pointing to that pointer, you need to look one byte later in RAM, thus you do Pic1+1

Hayleia · « **Reply #1736 on:** April 22, 2014, 02:18:05 pm »

It will draw the sprite pointed by Pc1+Z

Basically, if you do for example
[some hex]→Pic1
[same hex]
And then Pt-Off(0,,A++^8+Pic1) in a loop, it produces interesting results

You can also use that as an "array of sprites", like
[first sprite]→Pic1
[second sprite]
[etc]
Then the I^th sprite can be displayed with Pt-Off(X,Y,I*8+Pic1)

NikProgrammer · « **Reply #1737 on:** April 22, 2014, 02:48:42 pm »

I think that I understand everything except of the Pt-Off(0,A++^8+Pic1

Sorunome · « **Reply #1738 on:** April 22, 2014, 05:42:10 pm »

Ok, so I'm trying to get the user to press second and release it and pause the code until said thing happens.
I tried to things without success

Code: [Select]

:While 1
:EndIf getKey(54)
:While 1
:EndIf getKey(54)=0

Code: [Select]

:While 1
:EndIf getKey(54)
:While 1
:End!If getKey(54)

They should both work IMO, any ideas?

EDIT: Putting a Pause 6 into the loops made it work, why do you need a pause in the loops, though?

Streetwalrus · « **Reply #1739 on:** April 22, 2014, 07:29:59 pm »

I think it's a keyboard delay issue. Pause 5 always worked for me but nothing never did.
Keep in mind we have a nice cpu but all the hardware TI added is slow so io is affected a lot.

Author Topic: Axe Q&A (Read 587484 times)

josh landers

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NikProgrammer

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josh landers

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TheMachine02

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aeTIos

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Sorunome

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aeTIos

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Sorunome

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Hayleia

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NikProgrammer

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Sorunome

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Hayleia

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NikProgrammer

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Sorunome

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Streetwalrus

Re: Axe Q&A