Author Topic: Axe Q&A (Read 600163 times)

Sorunome · « **Reply #1755 on:** April 24, 2014, 05:55:16 am »

It is working, thanks!
Why couldn't i find this in the docs, though

TheMachine02 · « **Reply #1756 on:** April 24, 2014, 05:58:12 am »

there is a tuto about external file, and it is also talking about file here : http://www.omnimaga.org/axe-language/external-vars-tutorial/msg152571/#msg152571

Streetwalrus · « **Reply #1757 on:** April 24, 2014, 01:09:10 pm »

Also it's in the PDF IIRC.

There's actually more than Y0-9 but they have different purposes that I don't remember exactly and they're not in the doc, only in the changelog. By the way that works for reading from RAM, so it's quite versatile.

Runer112 · « **Reply #1758 on:** April 24, 2014, 06:04:08 pm »

Quote from: Streetwalrus on April 24, 2014, 01:09:10 pm

Also it's in the PDF IIRC. There's actually more than Y0-9 but they have different purposes that I don't remember exactly and they're not in the doc, only in the changelog.

Yeah. You can use Y_1T and Y_2T for variables in RAM (not using the file syntax, just normal like GetCalc(...)→Y_1T), and if the variable is moved, the pointers will be adjusted to continue to point to the same offset into the variable. Unfortunately, there can only be two of them, because TI (somewhat reasonably) decided to only support two.

Streetwalrus · « **Reply #1759 on:** April 24, 2014, 07:19:20 pm »

Oh wow is that actually a TI feature ? I guess they sometime have a genius idea and make useful things. Now I wish it is fast enough.

Sorunome · « **Reply #1760 on:** April 25, 2014, 05:02:32 pm »

Ok, now i have a For( loop behaving VERY oddly:
I have the for loop so that it modifies stuff, based on how a pointer is set

Code: [Select]

For(C,0,{GDB2})
4*C+GDB2->E
<stuff with E>
End

This does none of the modifications while the following does the first one:

Code: [Select]

For(C,0,{GDB2})
4*C+GDB2->E
4*0+GDB2->E
<stuff with E>
End

Which makes absolutely no sense to me as in the first run C will be equal to 0 and it should be able to do the first one.
It might be worthy to mention that I compile as an app.

EDIT: I just copied GDB2 now to some free ram before using it and it worked, I take it that you have to do so because I compile as an app?

Hayleia · « **Reply #1761 on:** April 25, 2014, 05:46:01 pm »

Well you can't (at least not that easily) store in Flash, which is exactly what you are doing when writing ->{Bleh+GDB2} when you compile as an app (and after declaring GDB2 as a pointer to somewhere in your executable).

Also, always (when you can obviously, not always always) put constants at the end. I mean, write C*4 and not 4*C.

Sorunome · « **Reply #1762 on:** April 25, 2014, 05:50:16 pm »

I was only reading off of it.

Runer112 · « **Reply #1763 on:** April 25, 2014, 05:56:55 pm »

I can't immediately see any reason why that would be behaving oddly. It might matter what the "stuff with E" is.

Also, since applications aren't modifiable, {GB2} can only be a constant. Why not pull out whatever value it holds as a constant?

Sorunome · « **Reply #1764 on:** April 25, 2014, 06:01:53 pm »

the stuff is this:
nib{E+1*2+1}->D
({L5+11} and D=D and ({L5+10}>=nib{E+q*2}) and (N={E}))?{E+3}->{L4+{E+2}}

And that way it is easier to me to modify my data when compiling, and also gives me the easy opportunity to move said data out of the app.

NikProgrammer · « **Reply #1765 on:** April 25, 2014, 06:42:53 pm »

Sorry that I'm breaking in but I have a question: I do a normal program in axe and can compile as 'No shell'. Why it says not enough ROM if I try to compile this program as an App?

Sorunome · « **Reply #1766 on:** April 26, 2014, 03:53:52 am »

Apps can only be up to 16384 bytes large.

NikProgrammer · « **Reply #1767 on:** April 26, 2014, 07:00:02 am »

It is less than 2000 bytes large...

Sorunome · « **Reply #1768 on:** April 26, 2014, 07:16:57 am »

Well, you also need at least 16384 bytes of free ROM, no matter the program size

Runer112 · « **Reply #1769 on:** April 26, 2014, 07:37:47 am »

Quote from: Sorunome on April 25, 2014, 06:01:53 pm

the stuff is this:
nib{E+1*2+1}->D
({L5+11} and D=D and ({L5+10}>=nib{E+q*2}) and (N={E}))?{E+3}->{L4+{E+2}}

Yup, the issue is in the "stuff with E". To read data from inside your program/application, you want to use nib{}^r. The nib{} command with no modifier always reads from the $8000-$FFFF address range (RAM), whereas the command with the modifier always reads from whichever range your code resides in: still $8000-$FFFF for programs, but $0000-$7FFF for applications.

Author Topic: Axe Q&A (Read 600163 times)

Sorunome

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Runer112

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