Huh. Perhaps Axe is parsing the , as a }

Good to hear, Quigibo! The first part is anyway.
sqrt(X²+Y²->{{{ºD-I}^r}+sin(5}}

Good to hear, Quigibo! The first part is anyway.
sqrt(X²+Y²->{{{ºD-I}^r}+sin(5}}

Taking a wild guess here:
Its taking the square root of X^2+Y^2 and storing it to the position of D-I, plus the sine of 5?

Quote from: Freyaday on July 05, 2011, 10:38:16 pm

Good to hear, Quigibo! The first part is anyway.
sqrt(X²+Y²->{{{ºD-I}^r}+sin(5}}

Taking a wild guess here:
Its taking the square root of X^2+Y^2 and storing it to the position of D-I, plus the sine of 5?

Not quite

It's taking the square root of X squared + Y squared and loading it in the byte pointed to by the sine of 5 plus the byte pointed to by the short pointed to by the address of D minus the value of I.  Close

No one is gonna try mine? :'(

so it's not valid...

Oh, it's perfectly valid.

Well then I'm correct

Then perhaps it does what Ashbad says, but it square roots everything last instead of first?

({{rand+nib{8/cos(SQRT(rand20)⁺8erandrand)16BITANDsin(->F)}}->{°Θ}^r/{_EFFFF xor L1))}16BITXOR{->{°C-4}^rr°A+{^Trand*85+rand^°C}}^r}//{rand+L1}²)**{F} and {5max(,)5}

This code is not valid Axe code. You have mismatched parentheses:

Depth: 0123        4     5    6      5          4           5   432  3  2 3           210
        ({{rand+nib{8/cos(SQRT(rand20)⁺8erandrand)16BITANDsin(->F)}}->{°Θ}^r/{_EFFFF xor L1))}    continued below...
Depth:          1  2    1     2               10 -1
        16BITXOR{->{°C-4}^rr°A+{^Trand*85+rand^°C}}^r}//{rand+L1}²)**{F} and {5max(,)5}

sqrt(X²+Y²->{{{ºD-I}^r}+sin(5}}

• Calculate (X²+Y)², save value for later.
• Load the address of the D variable, and offset this address backwards in memory I bytes.
• Load the word pointed by the address above.
• Load the byte pointed to by the word above.
• Add to this byte Axe's approximation of 127 times the sine of 5 binary degrees, which is 19.
• Attempt to store the low byte of the previously calculated X²+Y² to the byte pointed to by the address above. However, in the normal operational mode of the calculator, this address will point to flash so the write will fail.
• Calculate the square root of the value from 2 lines above, giving a final value of 4 to 16.

Alternatively, as one run-on sentence:

Attempt, but fail because flash is read-only, to store the low byte of x squared plus y, squared to the byte pointed to Axe's approximation of 127 times the sine of 5 binary degrees, which is 19, plus the byte pointed to the word pointed to the address of the D variable offset backwards in memory I bytes, and finally take the square root of the address to which x squared plus y, squared was attempted to be stored, giving a final value of 4 to 16.