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0->B->C->DFor(A,0,15)Pt-Off(0,A,{o}A)EndDispGraph
Very nice. As a side note:Code: [Select]For(A,0,15)Pt-Off(0,A,{o}A)EndDispGraphShould give the same thing. (except for the randomness of whatever is in B, C, and D){o}=o
For(A,0,15)Pt-Off(0,A,{o}A)EndDispGraph
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