So let's say I wanted to have a way to store two bits per pixel on the screen (768 bytes of data, * 2.) into RAM so I could manipulate it. How would I go about doing this, and which safeRam areas should I use (if I use L6, I'll just end up drawing directly to the screen, but I want 4scale as well, and I know it's possible.)

The first one, I'm guessing might be L3, and everytime I want to access data, I'll just do
for bit one:
{L3}+(number of pixel)
and bit two:
{other safeRam}+(number of pixel)
so to draw the screen, I just have to do a
DispGraph(L3,other safeRam)^r
So tl;dr, which safeRam besides L3 should I use for holding the entire screen?
Thanks in advance!

use L6, which is the main buffer

You're serious? Waht? Doesn't that corrupt buffer drawing or something? (btw, I don't understand that statement)

Good luck.

Looks like I'll need it. Thanks

Quote from: macweirdo on November 20, 2011, 05:01:41 pm

Quote from: ztrumpet on November 20, 2011, 04:58:04 pm

use L6, which is the main buffer

You're serious? Waht? Doesn't that corrupt buffer drawing or something? (btw, I don't understand that statement)

The main buffer is what gets displayed with a DispGraph.  If there's something else there, that will be drawn instead.
For instance, try this code and see if you can figure out what is happening:

Code: [Select]

:ClrDraw
:255->{L6}
:rand->{L6+766}r // This is the superscript r
:DispGraph
:Repeat getKey(15)
:End

So storing data there is just like doing a Pxl-On( to that buffer?

Quote from: ztrumpet on November 20, 2011, 05:07:58 pm

Quote from: macweirdo on November 20, 2011, 05:01:41 pm

Quote from: ztrumpet on November 20, 2011, 04:58:04 pm

use L6, which is the main buffer

You're serious? Waht? Doesn't that corrupt buffer drawing or something? (btw, I don't understand that statement)

The main buffer is what gets displayed with a DispGraph.  If there's something else there, that will be drawn instead.
For instance, try this code and see if you can figure out what is happening:

Code: [Select]

:ClrDraw
:255->{L6}
:rand->{L6+766}r // This is the superscript r
:DispGraph
:Repeat getKey(15)
:End

So storing data there is just like doing a Pxl-On( to that buffer?

Kind of.  It's just another way of drawing stuff.
Remember that the data on the buffer is stored in binary, and because of this 255 = FFh = 11111111b makes 8 pixels in a row black.

track your posts. You'll see which posts got derated.

Two things I must mention. First, buffers are 768 bytes. Second, creating a variable of size 766 in A and storing a value to A+766 will corrupt whatever is next in memory. Why is 3 being stored there, anyway?

Quote from: macweirdo on November 20, 2011, 07:48:36 pm

EDIT: why do I have -3 karma?

Because three people disliked this post and downvoted it.

Deleted it because I recently lost respect even though that post is ancient. Thanks for taking the time to find that post

EDIT To prevent a double post:

Just an FYI, if you absolutely needed more free ram and all the buffers are taken, you could create an appvar and use that:

Code: [Select]

getCalc("appvMYAPPV", 766)->A
3->{A+766}
DispGraph(L3,A)^^r

You could also do something like

Code: [Select]

Buff(766,0)->A
3->{A+766}
DispGraph(L3,A)^^r
...although you'd be adding the buffer directly to the program itself (inflating its size by 766 bytes) + I don't think you can modify buffers you have inside the program if you turn your program into an app.

I'm trying to keep it as fast as I can, but I'm never making it an App, this program might be less than 1500 bytes.
Can't wait to release my first Axe game