How does the frequency command work? If we wanted to play a C for a period of time, what would you put in and why?

Freq(1.29,1000)

I'm assuming no, since Axe doesn't work natively with decimals. Also, for smaller questions like these maybe you want to post them in the Axe Q&A thread here?

The Freq() command takes two arguments: wavelength and time. TBO_Yeong and linuxgeek96, I'm not sure where you got your wavelength numbers from, but neither of them appear to be correct. The approximate value that I got was 487, using this formula for the wavelength argument with middle C's frequency, 261.63Hz:

Wavelength argument = (6000000/frequency - 62)/47

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Now, to deal with the time argument. The formula for this is a little more complex, since it doesn't have an explicit form, only implicit:

Desired duration = (47*time argument + 48*floor(time argument/wavelength argument) + 71)/6000000

However, if we give floor(time argument/wavelength argument) an approximate constant value instead (I'll give it about 50), we can get an explicit form:

Time argument = (6000000/desired duration - 2500)/47

If we wanted a note length of 1/4 of a second, this would give us a time argument of approximately 31900.

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Putting it all together, to play middle C for about 1/4 of a second, you would use the following code: Freq(487,31900).