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Lbl Asub(A)
Code: (Axe) [Select]Lbl Asub(A)Same thing sub( is basically just CALL. That's all it is.
Lbl AIf r1=0 Return 1EndReturn r1*sub(A,r1-1)
Quote from: Deep Thought on May 31, 2011, 05:12:50 pmCode: (Axe) [Select]Lbl Asub(A)Same thing sub( is basically just CALL. That's all it is.So that's not like Pause 0, it's really infinite or does it break or something?
I also found Asm(3333 to work
Quote from: Hot_Dog on May 31, 2011, 08:18:45 pmI also found Asm(3333 to work Yeah, randomly increasing the stack pointer does seem to have that affect.And compiling the "Lbl A:Sub(A)" thing shows that it is in fact, just a straight call back to 9D95.
Quote from: graphmastur on May 31, 2011, 11:00:37 pmQuote from: Hot_Dog on May 31, 2011, 08:18:45 pmI also found Asm(3333 to work Yeah, randomly increasing the stack pointer does seem to have that affect.And compiling the "Lbl A:Sub(A)" thing shows that it is in fact, just a straight call back to 9D95.Lol, I meant increasing the stack pointer fixes the problem
I hear "Memory leak" a lot and generally know what it is on computers, but is it permanent memory loss on Z80 calculators?