Author Topic: Replace Pause x by Freq(a,b)  (Read 3974 times)

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Offline Keoni29

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Replace Pause x by Freq(a,b)
« on: September 23, 2011, 02:55:09 am »
I want to replace Pause x by Feq(a,b) so my question is: How many times does b fit in one second? I know that x fits 1900 times in one seconds, so: Xonesecond / Bonesecond
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Offline chattahippie

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Re: Replace Pause x by Freq(a,b)
« Reply #1 on: September 23, 2011, 06:54:35 am »
I read that it was about 128,000 ticks per seconds

Here's where it is
http://ourl.ca/7719

Offline Keoni29

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Re: Replace Pause x by Freq(a,b)
« Reply #2 on: September 23, 2011, 02:20:00 pm »
Sow this is a long note:
Code: [Select]
freq({n+Gbd2},6000
pause 20*S-C

And this is a short note:
Code: [Select]
freq({n+Gbd2},3000
pause 20*S-C+450
1900/128,000=0.15
3000/0.15=450

or even better:

long note:
Code: [Select]
freq({n+Gbd2},S*20-C*15+6000
short note:
Code: [Select]
freq({n+Gbd2},3000
pause 20*S-C+450
« Last Edit: September 23, 2011, 02:22:53 pm by Keoni29 »
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