You can always display them manually...

This displays the 32-bit number in the location Str1, but destroys the number afterwards. (range of 0 to 4,294,967,295)

Lets Make Str1 hold 9000*9000 = 81,000,000  In Hex, that's 4D3F640.

Code: [Select]

:[04D3F640]->Str1
:
:For(D,0,9)
:0->A
:For(B,0,3)
:A*256+{Str1+B}->C^10->A
:C/10->{Str1+B}
:End
:Output(15-D,0,A+'0'▶Frac)
:End
:Disp i

Of course, you can extend this to any arbitrary length.

Please don't ask me how this works.  I looked up the algorithm on the learn z80 in 28 days tutorial.  I kind of see why it might work, but I don't really know it enough to explain.