Author Topic: Trigonometric functions (tan, arctan) in axe (Read 2913 times)

bilyp · « **on:** November 15, 2011, 01:10:55 am »

How would you go about doing trigonometric functions in axe, like the arctan (tan^-1()), to calculate the reverse of the tangent or sine of an angle.
I looked all over the internet, but all I could find was that tan(X) = sin(X)/cos(X), nothing about calculating the arctangent.

Quigibo · « **Reply #1 on:** November 15, 2011, 06:17:58 am »

A surprisingly accurate approximation for arctangent is:

Code: [Select]

atan(x) ≈ (π/2)*x/(abs(x)+1)
Which, when converted from radians, can be implemented in fixed point notation as x*64//(abs(x)+256) however this has overflow problems in the numerator. Fortunately you can perform long division to reduce it to 64-(16384//(abs(x)+256)) which accounts for everything except the sign. This can be done with a simple if statement:

Code: [Select]

:Lbl atan
:64-(16384//(abs(r1)+256))→r2
:If r1<<0
:  Return -r2
:End
:Return r2

bilyp · « **Reply #2 on:** November 15, 2011, 07:34:51 pm »

Wow. That is perfect, exactly what I needed! Thank you for this, it answers my question!

Author Topic: Trigonometric functions (tan, arctan) in axe (Read 2913 times)

bilyp

Trigonometric functions (tan, arctan) in axe

Quigibo

Re: Trigonometric functions (tan, arctan) in axe

bilyp

Re: Trigonometric functions (tan, arctan) in axe