Quote from: calc84maniac on June 17, 2011, 12:43:52 am

I recommend storing in decimal because he's going to have to output the values in human-readable format. I assume he won't want to make a routine to extract decimal digits from a large binary number.

It's not terribly difficult to convert to decimal, but yeah.

Example psuedo-code for Hex array->Dec:

Code: [Select]

int arraysize;
char *array;
char *output;
int j = 0;
For(i,i<arraysize,i++) {
stream = *array[i];

if stream>0x0A {
*array[j] = 0x31;
j = j+1;
stream = stream % 10;
}
*array[j] = stream + 0x30;
j = j+1;
}


That's assuming each byte holds a value from 0-99 (or 0x00 to 0x63 if you prefer). Binary numbers are in base 2, not base 100.

Oh yeah, cause when you display 0xFFFF, it turns out as 15151515! Nice to know

Well, you're not declaring x to be anything but null, so..

He means you are not initializing X with a value, you are just going int X or double X, which creates the variable, but it holds no value.

He means you are not initializing X with a value, you are just going int X or double X, which creates the variable, but it holds no value.

double x;
scanf("%lf",&x);
I get it through input.

Try this? It's just a different method of calculating the factorial.

#include <stdio.h>

int main();
double factorial(double n);

int main() {
   
    int n;
   
    scanf("%d",&n);
   
    int i;
    for (i=0;i<n;i++)
    {
        double x;
        scanf("%lf",&x);
        printf("%lf\n",factorial(x));
    }
   
    return 0;
}

double factorial(double n)
{
    if ((n == 1) || (n == 0))
    {
        return(1);
    }
    else
    {
        return(n * factorial(n - 1));
    }
}