Hello!  Welcome to Omnimaga.

You shouldn't worry about people stealing your program.  If somebody does do that, then the community tends to get VERY angry at them (and shun them, and ban them, and dislike them in every way...  Of course, looking at other people's code, and sharing ideas are highly encouraged.  The calculator community tends to be very open-source).  Of course, accusations of theft are equally disliked, which got a few people in trouble a while back when they got too paranoid.

1) If you don't like the idea of having to store x and y coordinates into two vars, you could just use modulus to combine them into one.  If I do this:
335->A
Then I could extract the x-intercept by doing 335^255 (which is 335 mod 255, which returns 80) and the y-intercept by doing 335/255 (which returns 1, because there are no decimals in Axe.)
So basically, to store coordinates into one number, X-intercept+(255+Y-intercept)->variable.

2) To do sound, use the Freq( command.  I don't know the exact numbers, but try experimenting with Freq(1250,(add any multiple of 1250 here)).  This should get you a sound that is relatively low.  (Of course, you need 2.5mm headphones to listen to sound with the calc...)

3a)  First, you don't really need decimals at all.  If I wanted to use decimals, I could just multiply the number by 100 (or better yet, 255), manipulate it, then divide it by 100 (or whatever you're inflating it with) when displaying on the screen (because a 64x96 screen is pretty inaccurate to begin with)
That being said, I'm not entirely certain how I would make a project follow a parabolic path, but I would try adding gravity, simulating how much power is in the projectile, and simulate real life.  You should probably ask Builderboy.  He's good with physics.

3b) Inflate all the numbers (let's pick an inflation number of 255, because it's cool), use the standard y=mx+b slope formula, find out what the next number is, then divide by 255 (or the inflation number) again.  Then use Pt-On (or whatever similar command)

4) Number^2
If this returns 1, it's odd.  If it returns 0, it's even.  (or perhaps its the other way around, but you should be able to figure it out)

Edit: Apologies if I didn't make much sense, or made mistakes - I'm a bit sleepy.

You're welcome
Let us know if you have any other questions!  Hope your project works out!

ive been working on doodlejump for the calculator for about a week now. i thought it would be a great idea and i did it and added sound...however its only halfway complete but already addictive and attractive...i think i've took it to a point where all that is missing is the monsters and shooting.btw..do not steal my idea to make doodlejump!
...
3a. How do i make a projectile follow a parabolic path (in Ti-Basic you can do Pt-On(34.56,x²+2x+C) but in axe its all integer numbers so i cant do Line(2.5,3.5,4.5,1/3...i think thats a major downfall...)
3b.How do i make a ball/bullet follow a linear path(line) that is at any angle...basically how can i make a pixel follow a linear equation?
4. major question here...this will solve problem 3 for me...wheres the precious int( command? how do i know if a number is even without going ":if A/2=int(A/2"? how can i do int(3.45x+3) in axe?

I think I saw a topic labeled DoodleJump around here recently...

Anyway, the main difference between Axe and BASIC is that there are no decimals in Axe. None at all [barring Assembly work]. The easiest way to have projectile motion is to forget about realistic numbers and realize that you're working on a pixelated screen. Thus, you can give objects vectors in the form of moving a certain number of pixels per frame. Thus, a ball with no horizontal motion might move 0 pixels left or right, but could drop a constant 3 pixels per frame or something.This also solves the linear path problem because all you would have to do is set the position change variables constant. If you want to get into acceleration, that's also possible, but it requires some additional steps.

question 3b will be answered once i recall my knowledge of the sin/cos routines.

Hint: They return a value between 0 and 255 and are normal otherwise.

Quote from: nemo on December 09, 2010, 07:23:48 pm

question 3b will be answered once i recall my knowledge of the sin/cos routines.

Hint: They return a value between 0 and 255 and are normal otherwise.

no, they return a value between -127 to 127. and they are not normal otherwise. they have a period of 256, not 2pi.

also, i was thinking of the problem of making a routine which retains a constant speed while being able to change your direction. linear bullets are easy because you just have an x velocity and y velocity, like michael lee said.

To get lists in Axe, there are things called free ram and pointers. 

But first, I should go over how memory works in Axe, which you can skip over if you already know about bits and bytes.
At the very basic level, everything is ones and zeros.  This is binary.  Each one and each zero is referred to as a 'bit'
Axe uses something called bytes to manage memory.
A byte is comprised of exactly 8 bits.
So if 1 is a bit, and 0 is another bit, then 10110001 is exactly one byte.
One byte can hold numbers equal to 255 or under.
However, this often isn't big enough, so Axe allows you to use two bytes in a row to hold numbers up to 65535 (which is 256*256-1).
I like to imagine bytes as houses, all lined up in a row.  A bit is like a (tiny) room in that house, and two houses together can hold A LOT of people.
But we have to know where each house is, which is why they all have addresses.  We call those addresses pointers.

Which brings us nicely to free ram.
The symbol L₁ is a address that points (hence the name pointer) to a 710-byte-long block of free RAM that you can use as you please.
By adding a number to the pointer, we can get access to other bytes besides the first one.
Also, by adding brackets around the pointer, we can then manipulate what number is actually stored in that byte instead of just manipulating the address.

So, L₁+5 would get me the address fifth byte of free ram and {L₁+5} would get me whatever number I've put there.
Examples:
.CODE1
1->{L1}
1->{L1+1}
2->{L1+2}
3->{L1+3}

For(A,0,3)
  Disp {L1+A}->DEC,i      //imaginary i for newline, here
End

Pause 5000  //added for completeness - now a functional program!
The For loop would display the numbers I had placed into free RAM earlier, displaying
1
1
2
3

To get two-byte numbers, I would just do something like {L₁+A}^r
The 'r' makes that pointer return the two-byte number (using the one following the pointer for the second byte)

L₂ to L₆ also return pointers to more free RAM, but you should check the commands list because the amount of available bytes varies, and L₆, for example, is used by Axe to store what your program is displaying on the screen, so messing with the other 5 pointers besides L₁ can have some inconvenient consequences.

lol, a lot of Doodle/Papi Jump ports lately 
but anyway, good luck, can we haz screenies soon?