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Note that you have to compile the code yourself into hex using the binary table registers are 00 for A, 01 for B 10 for C and 11 for D. And for jumps 00 is jump if Zero, 01 is jump if carry, 10 is jump if Not Zero, and 11 is jump if not carry
ld a, $69 ld ($0102), a ld a, $FF ld a, ($0102)
Yay, I fixed it. The current instruction register was outputting a 6 just before it got changed to 1. So I just bypassed it for phase 1 and it worked. Off to make a text routine.Thank you
Oh my wow. Screw programming in hex, I am already loving this. Thank you, I am going to have so much fun with this.