not quite, since that makes the variable smaller, when you want to be making it larger.  adding 255 would work though.

If this: 23.156 is your Y value, you are on the 23rd pixel, and 156/256 the way down the pixel.  We want to be at the very bottom, we want to be at 23.255, so we want to set the second half to 255.  We can do OR 255, we can try /256*256+255, or 255->{oY}. whatever we like

yeah, its the symbol used to find the address of the Y variable, that way I can set the specific byte that corosponds to it

It is a boolean, but it works on each individual bit of the number Since your number is 10101001.10010010 , and since we want the second half to be 11111111, we just OR your number with 11111111 (255), which sets all of the bits to 11111111

It still is boolean remember the calc only operates in 1's and 0's no matter what, this just acts like a whole bunch of boolean OR's for each bit in the number

I'm guessing 255 will do it, since that will put you at the lowest possible spot without moving into the next pixel, but i cant be sure o.O

No i mean lowest possible spot on the screen (i've been talking about Y position) since higher numbers move down the screen

yay ^^