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I've got another question that may seem simple. How does one do Polynomial division?...To do division, I have to go to the on screen menu, select CAS, select Polynomial, Algebra, Quotient,
Also, one thing I just noticed: If I wanted to find the limit of, say, 1/x as x goes to zero from the positive side, I have to enter "1" instead of just entering "+", likewise if i wanted to find it from the negative side, I would have to enter "-1" instead of just "-".
Nearly there. Put your first poly in the first argument, and the second in position 2. Just like the nspire, it is a 2 argument function.quo(x^7+4x^3+8,x^2+2)
That seems like a lot of steps to get to something that occurs fairly often. Why can't I just do (polynomial 1)/(polynomial 2) for division?
Quote from: sailerboy on September 27, 2013, 04:47:30 pmThat seems like a lot of steps to get to something that occurs fairly often. Why can't I just do (polynomial 1)/(polynomial 2) for division?Is your Simplify level on Off? If it is, remember that the CAS won't change your variables at all. I always have it on Maximum.
Quotequo(x^7+4x^3+8,x^2+2)That seems like a lot of steps to get to something that occurs fairly often. Why can't I just do (polynomial 1)/(polynomial 2) for division?
quo(x^7+4x^3+8,x^2+2)
Today's Bug:
Today's Suggestion: the right arrow character should be a synonym for -> in the CAS. Having -> when a perfectly good UTF character exists is quite odd.
Another bug: Trying to differentiate the equation (2/3)(x^2+1)^(3/2) gives weird output. Here is the image:
Quote from: SpiroH on September 28, 2013, 09:22:17 amQuote from: sailerboy on September 28, 2013, 12:17:31 amAnother bug: Trying to differentiate the equation (2/3)(x^2+1)^(3/2) gives weird output. Here is the image:Yeah, that's a very odd output indeed, to say the least? I wonder, have they thoroughly tested symbolic differentiation?The problem is not the differentiation, the problem is even earlier in the interpretation of the expression (2/3)(x^2+1)^(3/2).If you enter the same expression but with an explicit multiplication character, i.e. (2/3)*(x^2+1)^(3/2), then everything works fine.But without this * after (2/3) this expression seems to a completely different thing, not even an usual math expression but a 'function' like f((x^2+1)^(3/2)) with '2/3' as 'name' of the function, i.e. '2/3'(.....). And that's the reason why the differentiation doesn't work for this 'function' of course!Just try to experiment a bit with this strange expression and you'll see that is not anything you would expect - crazy indeed!Franz
Quote from: sailerboy on September 28, 2013, 12:17:31 amAnother bug: Trying to differentiate the equation (2/3)(x^2+1)^(3/2) gives weird output. Here is the image:Yeah, that's a very odd output indeed, to say the least? I wonder, have they thoroughly tested symbolic differentiation?
I wonder, have they thoroughly tested symbolic differentiation?