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∭∞-∞(√(x²+y²+z²)e-(x²+y²+z²)))dxdydz =2ㅠThe reason why is very fun to figure out, but should be rather obvious to some people
Quote from: squidgetx on March 02, 2011, 06:35:37 pm1+2+3+4...=-1/12Remind me again how this can be even remotely possible? There seems to be no way to get that to work
1+2+3+4...=-1/12
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Formula for finding prime numbers.(k + 2)(1 −[wz + h + j − q]2 −[(gk + 2g + k + 1)(h + j) + h − z]2 −[16(k + 1)3(k + 2)(n + 1)2 + 1 − f2]2 −[2n + p + q + z − e]2 −[e3(e + 2)(a + 1)2 + 1 − o2]2 −[(a2 − 1)y2 + 1 − x2]2 −[16r2y4(a2 − 1) + 1 − u2]2 −[n + l + v − y]2 −[(a2 − 1)l2 + 1 − m2]2 −[ai + k + 1 − l − i]2 −[((a + u2(u2 − a))2 − 1)(n + 4dy)2 + 1 − (x + cu)2]2 −[p + l(a − n − 1) + b(2an + 2a − n2 − 2n − 2) − m]2 −[q + y(a − p − 1) + s(2ap + 2a − p2 − 2p − 2) − x]2 −[z + pl(a − p) + t(2ap − p2 − 1) − pm]2)> 0Strangely enough I made a program on calc and computer that use this formula but I never got it to work.
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Topic: Favorite math theory/rules/law/et cetera. (Read 16928 times)
