Author Topic: Favorite math theory/rules/law/et cetera.  (Read 17083 times)

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Offline Hot_Dog

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Re: Favorite math theory/rules/law/et cetera.
« Reply #15 on: March 02, 2011, 07:34:34 pm »
I like Fermat's Last Theorem, as well as the Trapezoid Rule

Offline Deep Toaster

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Re: Favorite math theory/rules/law/et cetera.
« Reply #16 on: March 02, 2011, 09:03:58 pm »
-∞(√(x²+y²+z²)e-(x²+y²+z²)))dxdydz =2ㅠ

The reason why is very fun to figure out, but should be rather obvious to some people ;)

I didn't even know there was a triple-integral character O.O

Oh, and vertical integration (for APUSH nerds):


f(x)
dx
« Last Edit: March 02, 2011, 09:04:38 pm by Deep Thought »




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Re: Favorite math theory/rules/law/et cetera.
« Reply #17 on: March 02, 2011, 09:20:28 pm »
AP US history ???

Offline z80man

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Re: Favorite math theory/rules/law/et cetera.
« Reply #18 on: March 02, 2011, 09:26:14 pm »
1+2+3+4...=-1/12

Remind me again how this can be even remotely possible?  There seems to be no way to get that to work O.O
It seems that you have forgotten that when numbers exceed 32,767 they return to -32,768, therefore allowing a sequence of 1+2+3+4.... to be less than 1. ;)

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Offline Deep Toaster

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Re: Favorite math theory/rules/law/et cetera.
« Reply #19 on: March 02, 2011, 11:17:35 pm »
Well, it's the same basic idea as those proofs that show 0=1: when you deal with infinite numbers in the wrong way, weird things happen :D

AP US history ???

http://en.wikipedia.org/wiki/Vertical_integration

Like Carnegie's monopoly over the steel industry.




Offline ruler501

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Re: Favorite math theory/rules/law/et cetera.
« Reply #20 on: March 02, 2011, 11:28:25 pm »
I like the fact that from that you can seemingly prove infinity equals negative one half

1+1=1+1+1+1+1+1+1+1+... is an infinity of ones added together so it equals 1*infinity
1+1+1+1+1+1+1+1+1+1+...=-1/2 divide both sides by one and you get infinity equals -1/2
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Re: Favorite math theory/rules/law/et cetera.
« Reply #21 on: March 02, 2011, 11:30:45 pm »
You didn't do your order of operations ;)

Offline yunhua98

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Re: Favorite math theory/rules/law/et cetera.
« Reply #22 on: March 03, 2011, 06:12:52 pm »
Distributive law.   :P

jk, they're all great.  ;)

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Re: Favorite math theory/rules/law/et cetera.
« Reply #23 on: March 03, 2011, 06:48:16 pm »
I love how Euler's identity includes all the principal mathematical constants in the same formula.


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Re: Favorite math theory/rules/law/et cetera.
« Reply #24 on: March 03, 2011, 07:33:55 pm »


Buttefly Effect! LOL I don't know what the equation is about, but I love the concept behind the Butterfly Effect
« Last Edit: March 03, 2011, 07:34:56 pm by jsj795 »


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Re: Favorite math theory/rules/law/et cetera.
« Reply #25 on: March 04, 2011, 08:16:24 am »
ln (-1)
------  =  Chuck Norris
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 :P
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Offline yunhua98

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Re: Favorite math theory/rules/law/et cetera.
« Reply #26 on: March 04, 2011, 09:07:27 am »
ln(-1)=(pi)(i)

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Re: Favorite math theory/rules/law/et cetera.
« Reply #27 on: March 04, 2011, 07:57:59 pm »
Formula for finding prime numbers.

(k + 2)(1 −
[wz + h + j − q]2 −
[(gk + 2g + k + 1)(h + j) + h − z]2 −
[16(k + 1)3(k + 2)(n + 1)2 + 1 − f2]2 −
[2n + p + q + z − e]2 −
[e3(e + 2)(a + 1)2 + 1 − o2]2 −
[(a2 − 1)y2 + 1 − x2]2 −
[16r2y4(a2 − 1) + 1 − u2]2 −
[n + l + v − y]2 −
[(a2 − 1)l2 + 1 − m2]2 −
[ai + k + 1 − l − i]2 −
[((a + u2(u2 − a))2 − 1)(n + 4dy)2 + 1 − (x + cu)2]2 −
[p + l(a − n − 1) + b(2an + 2a − n2 − 2n − 2) − m]2 −
[q + y(a − p − 1) + s(2ap + 2a − p2 − 2p − 2) − x]2 −
[z + pl(a − p) + t(2ap − p2 − 1) − pm]2)
> 0

Strangely enough I made a program on calc and computer that use this formula but I never got it to work. :(

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Offline Hot_Dog

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Re: Favorite math theory/rules/law/et cetera.
« Reply #28 on: March 04, 2011, 08:16:10 pm »
I don't know who discovered this equation, but I call it the "mosquito curve" and I found it by accident.  (This is in polar graphing)

r = sin(cos(tan(theta)))
« Last Edit: March 04, 2011, 08:16:49 pm by Hot_Dog »

Offline phenomist

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Re: Favorite math theory/rules/law/et cetera.
« Reply #29 on: March 04, 2011, 09:13:56 pm »
Formula for finding prime numbers.

(k + 2)(1 −
[wz + h + j − q]2 −
[(gk + 2g + k + 1)(h + j) + h − z]2 −
[16(k + 1)3(k + 2)(n + 1)2 + 1 − f2]2 −
[2n + p + q + z − e]2 −
[e3(e + 2)(a + 1)2 + 1 − o2]2 −
[(a2 − 1)y2 + 1 − x2]2 −
[16r2y4(a2 − 1) + 1 − u2]2 −
[n + l + v − y]2 −
[(a2 − 1)l2 + 1 − m2]2 −
[ai + k + 1 − l − i]2 −
[((a + u2(u2 − a))2 − 1)(n + 4dy)2 + 1 − (x + cu)2]2 −
[p + l(a − n − 1) + b(2an + 2a − n2 − 2n − 2) − m]2 −
[q + y(a − p − 1) + s(2ap + 2a − p2 − 2p − 2) − x]2 −
[z + pl(a − p) + t(2ap − p2 − 1) − pm]2)
> 0

Strangely enough I made a program on calc and computer that use this formula but I never got it to work. :(

If I remember correctly, k is prime iff there exists a Diophantine solution on the other variables. (aka: practically, this formula is "computationally useless" :P) You'd need to solve for the other 25 or so integer variables such that the inequality holds; not an easy task :P
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