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Offline 42vs.1337

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Re: Geometry Question
« Reply #30 on: June 30, 2011, 04:12:47 pm »
you could simply use coordianate(bash) -or to make it sound better analytical geo.
let a=0,0 b=30,0 c=0,40.
the equation of bc is y-40=-4x/3
the distance (using the point to line formula) from 0,0 is just 24!!!!!!(factorial?)
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Offline AngelFish

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Re: Geometry Question
« Reply #31 on: June 30, 2011, 04:13:11 pm »
What the...?

EDIT: I can vaguely understand that post after spending a few minutes trying to decipher it.
« Last Edit: June 30, 2011, 04:14:18 pm by Qwerty.55 »
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∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ

Offline 42vs.1337

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Re: Geometry Question
« Reply #32 on: June 30, 2011, 04:37:17 pm »
Quote from: Qwerty.55 on June 30, 2011, 04:13:11 pm
What the...?

EDIT: I can vaguely understand that post after spending a few minutes trying to decipher it.
http://www.intmath.com/plane-analytic-geometry/perpendicular-distance-point-line.php
that problem is actually sort of trivial .........no offense guys.
i don't know but the area olution was a very standard method if you seen it before
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Offline fb39ca4

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Re: Geometry Question
« Reply #33 on: June 30, 2011, 04:47:20 pm »
Quote from: 42vs.1337 on June 30, 2011, 04:37:17 pm
Quote from: Qwerty.55 on June 30, 2011, 04:13:11 pm
What the...?

EDIT: I can vaguely understand that post after spending a few minutes trying to decipher it.
http://www.intmath.com/plane-analytic-geometry/perpendicular-distance-point-line.php
that problem is actually sort of trivial .........no offense guys.
i don't know but the area olution was a very standard method if you seen it before
Ummm...he's not using coordinates.

When you take the perpendicular from the base to the opposite corner, do you get two similar triangles?
« Last Edit: June 30, 2011, 04:52:43 pm by fb39ca4 »
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Offline aeTIos

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Re: Geometry Question
« Reply #34 on: July 01, 2011, 08:59:19 am »
Hm I am actually not bad with trigonometry. You can solve it with sinus this way:
∠α = tan(40/30) ≈53.13°
sin(α) = sin(53.13°) =0.8
30*0.8 =  24 (since sin gives the ratio of the opposite side to the hypotenuse)


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