I'm happy i understood what you typed and what I am writing about in my book(mostly )
Thanks again for the help

Imaginary numbers of the form a+bi where b=0 can be prime. ;-)  Technically, a+bi would have to only have multiples of 1 and itself.  I'm sure you could generalize the multiplication of to complex numbers to get another.  For example with P+Qi and S+Ti:
(P+Qi)(S+Ti)=PS+QSi+PTi+QTi^2=PS+QSi+PTi-QT=PS+PTi-QT+QSi=P(S+Ti)-Q(T+Si)
So, I guess as long as (PS-QT)=a and (PT-QS)=b, and as long as there were no P, Q, T, and S that satisfied that, it would be prime.

This is only in theory.  If the idea of being prime isn't extended to complex numbers, then... yeah.

Now I'm kondof confused. Must think about this...
Are prime numbers only the natural numbers?

Well, technically, it is defined as a natural number, so yes.  However, I believe you could extend the pretext of it to other numbers.  For example, above, if you had 0 for Q and T, you would get:
P(S+Ti)-Q(T-Si)=PS=A+Bi=A.  So, the factors of A would be P and S.  So it makes sense.  Take Q=2 and T=5:
P(S+Ti)-Q(T-Si)=P(S+5i)-2(5-Si)=PS+5i-10+2Si=S(P+2i)+5i-10
and P=9, S=3:
3(9+2i)+5i-10=27+6i+5i-10=17+11i
So the factors of 17+11i are (9+2i) and (3+5i) so 17+11i wouldn't be prime by this definition.

But yeah, it's defined as natural (real) numbers only.