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Author Topic: Calc II Work Question Help D:  (Read 3241 times)

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Offline Yeong

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Calc II Work Question Help D:
« on: September 12, 2012, 03:17:02 pm »
All right, I have this question:
A tank is is half full of oil that has a density of 900kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 for g and 3.14 for pi. Round your answer to three significant digits.)



r=3
h=1

I don't know how to work this one since the tank is only half full. :\ Apparently diving the full one by 2 doesn't work. Why is that?

EDIT: So for full one, I know that I do integral (900*9.8*pi(9-y^2)*(4-y)) from -3 to 3.
So if I want to do the half one, (900*9.8*pi(9-y^2)*(7-y)) from 0 to 3, right?
« Last Edit: September 12, 2012, 04:04:17 pm by yeongJIN_COOL »
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Offline ruler501

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Re: Calc II Work Question Help D:
« Reply #1 on: September 12, 2012, 05:38:02 pm »
Are you given the equation for the tank or can you assume its a sphere with a spout on top?
If you can assume its a sphere I'd use the equation for that otherwise integrate the function solved for x for -3 to 0 I'd assume(assuming that the bottom is -3 and top is 3)
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