I bet it has to do with taylor series for e^x and pi

hey, that's my favourite equation!
it's not really worth anything, but it definitely looks pretty.

That is, in my opinion, the most beautiful mathematical formula ever It uses the 5 most important numbers, uses 3 numbers from each large field of mathematics (i for imaginary, e for logarithmic, and pi for trigonometry) and it uses the 3 main mathematical operations (addition, multiplication, exponentiation)

And it is a very useful equation, too! I ♥ it.

And it is a very useful equation, too! I ♥ it.

How do you use it?

That is, in my opinion, the most beautiful mathematical formula ever It uses the 5 most important numbers, uses 3 numbers from each large field of mathematics (i for imaginary, e for logarithmic, and pi for trigonometry) and it uses the 3 main mathematical operations (addition, multiplication, exponentiation)

Not to mention it's even set equal to zero. And you forgot to mention that the other two numbers (1 and 0) are pretty important in math two. Both the identity numbers at once

Think about how you would do something like raising something to an imaginary power You can set up ratios and stuff and do more stuff and stuff. Also, e^(ix)=cos(x)+isin(x), so 3^i would be cos(ln(3))+isin(ln(3))

EDIT: so you can say with that the idea that e^(i2pi)-1=0 (that is i times 2 times pi)

so what you are saying is that e^i*n*pi)-1=0 where n is any natural number(possibly negative)

this is confusing could someone please explain how you bring numbers to imaginary powers and why you do it that way. I did not think you could bring a number to two separate powers and still have them equal the same number

so what you are saying is that e^i*n*pi)-1=0 where n is any natural number(possibly negative)

Nope, e^2nπi-1=0, while e^(2n+1)πi+1=0.