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Offline aeTIos

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Re: CAS Theory
« Reply #30 on: June 14, 2011, 03:18:17 am »
Seconded. I haven't made any progress this weekend, we went to a camping. I hope to make progress soon.
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Offline AngelFish

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Re: CAS Theory
« Reply #31 on: October 25, 2011, 09:48:22 pm »
Here's an Axe backup that I'm fairly sure contains an infix to RPN converter (and I don't have a link cable to restore it to .8xp state). I remember commenting it fairly heavily, so the code should be relatively self-explanatory.
« Last Edit: October 25, 2011, 09:48:35 pm by Qwerty.55 »
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∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ

Offline mrmprog

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Re: CAS Theory
« Reply #32 on: October 25, 2011, 10:32:27 pm »
Great job on this! I am very curios about how you are planning to do this. I am interested in CAS systems, but I don't think my understanding of them is good enough to make one. Where did you learn the concepts you used in this?
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Offline alberthrocks

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Re: CAS Theory
« Reply #33 on: October 25, 2011, 11:08:37 pm »
Quote from: mrmprog on October 25, 2011, 10:32:27 pm
Great job on this! I am very curios about how you are planning to do this. I am interested in CAS systems, but I don't think my understanding of them is good enough to make one. Where did you learn the concepts you used in this?
If you're referring to me, I don't have a clue :P I just make up theories that I think will work...

Qwerty, on the other hand... he's amazing, that's all! ;)
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Offline AngelFish

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Re: CAS Theory
« Reply #34 on: October 25, 2011, 11:13:32 pm »
Quote from: mrmprog on October 25, 2011, 10:32:27 pm
Great job on this! I am very curios about how you are planning to do this. I am interested in CAS systems, but I don't think my understanding of them is good enough to make one. Where did you learn the concepts you used in this?

If that was directed towards me, libraries and Google ;)

If you're curious about the actual algorithms, some good resources are "Algorithms for Computer Algebra" and Wikipedia.

Thanks, Alberthro
« Last Edit: October 25, 2011, 11:13:58 pm by Qwerty.55 »
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∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ
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