yea summer school stinks

currently ive decided to work on the battle engine i figure once that is close to done ill start everything else again
im just having trouble (im really bad at like large equation writing) writing the equation that will check all of the units on the field that are enimies for locstion and probability of hitting them (like accuracy)

any help / ideas on how to do this would be nice

one thing i think would work is to use a list for the troops kind of built like this

L1(1) # of units on field
L1(2) unit type
L1(3) x pos
L1(4) row
L1(5) # team   (start of unit one)
L1(6) continue with L1(2) here   (start of unit 2)
L1(3) L1(3) here
and so on and so forth

what do you think
oh and
im not going to be on irc untill school next year

ok thanks that means im not totally screwed up in the head

oh what would be more effective for the loop (not optiminzation wise speed wise)

while <var> <not equal to > L1(1)

or

for <var>,0,L1(1)


im having trouble figuring out wbhich would be faster?

i love the photos in the sig eeems  Gimp?

for(n,0,L1(1)-1  ; sets troop that is being checked
3+4N ->a ;sets its xpos to a 
for(b,0,L1(1)-1 cycles through all troops
3+4b -> c stores the troops xpos in to c
if L1(5+4n)=1 ;if troop is on team 1
then
if L1(c) <= L1(a)+(L1(a-1)*4)  and L1(c) >= L1(a); if xpos less than or equal to and xpos doen not equal less than the troops location
then
if L1(c+2) = 2 ;if on the opposite team
randint(1,3
if ans=2 ; accuracy
3 -> L1(a-1+4B) ; put 3 in unit slot to signify dead/ no troop
end
end
if L1(5+4n) = 2
then
if L1(c) >= L1(a) - (L1(a-1)*4) and L1 (c) <= L1(a)
then
if L1(c+2) =1
randint(1,3
if ans = 2
3 -> L1(a-1+4B)
end
end
end
end



what do you think it is the check code for crimson
well part of it

Unfortunately I have trouble understanding people code and what it does, since I am more visual (screenshots) but I did some small optimizing through the code (maybe some other people could spot more advanced optimizations) and saved half a dozen of bytes:

For(n,0,L1(1)-1
3+4N ->a
for(b,0,L1(1)-1
3+4b -> c
if 1=L1(5+4n
then
if L1(c) >= L1(a) and L1(c) <= L1(a)+(4L1(a-1
then
if 2=L1(c+2
randint(1,3
if ans=2
3 -> L1(a-1+4B
end
end
if 2=L1(5+4n
then
if L1 (c) <= L1(a) and L1(c) >= L1(a) - (4L1(a-1
then
if 1=L1(c+2
randint(1,3
if ans = 2
3 -> L1(a-1+4B
end
end
end
end

L1(1) # of units on field
L1(2) unit type
L1(3) x pos
L1(4) row
L1(5) # team   (start of unit one)
L1(6) continue with L1(2) here   (start of unit 2)
L1(3) L1(3) here
and so on and so forth

what if you did this?

N : Number of troops
L1: Unit Type
L2: Row
L3: Col
L4: #team

and then each troop would be represented by a single number, and their data would be in the element corresponding to that number.

ooops
troops are 8*8 (the tank can be longer so can planes)
buildings are 8*16  (8 high 16 long)

Use something like imageshack or some other hosting provider.

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