Author Topic: Programming Speed  (Read 10959 times)

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Offline Raylin

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Re: Programming Speed
« Reply #30 on: June 02, 2010, 07:19:11 pm »
The seq() command returns a list.

For example:
Code: [Select]
seq(X^2,X,1,3would return
Code: [Select]
{1,4,9}
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Offline ztrumpet

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Re: Programming Speed
« Reply #31 on: June 02, 2010, 07:21:15 pm »
The TI manual is very unoptimized, but how would you use sum( the way you used it? Doesn't the first argument have to be a list?
Oh, sorry, I thought it was used for summing a list.  If you're not using a list, then TI's correct.  My bad. :)

Offline Deep Toaster

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Re: Programming Speed
« Reply #32 on: June 02, 2010, 07:23:29 pm »
The seq() command returns a list.

For example:
Code: [Select]
seq(X^2,X,1,3would return
Code: [Select]
{1,4,9}

I didn't mean the sum(seq([exp],[var],[start],[finish] combination. I meant that I didn't understand the bit of code ztrumpet suggested:

]WHAT?!
This was in TI's manual?  I hope they know that sum([exp],[start],[finish] is smaller and faster.  What was TI thinking! :D
Which manual was it, 2.43 or 2.53?

It doesn't work on my TI-83 Plus, for some reason. It can only take a list as the first argument. Is it different on the 84 Plus series?
« Last Edit: June 02, 2010, 07:28:22 pm by Deep Thought »




Offline ztrumpet

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Re: Programming Speed
« Reply #33 on: June 02, 2010, 07:25:15 pm »
No, it's only for a list.  I was thinking the sum(seq([exp],[var],[start],[finish] was to be used on a list (with a list as [exp] ).  Sorry about this misunderstanding. :)
« Last Edit: June 02, 2010, 07:25:41 pm by ztrumpet »

Offline Deep Toaster

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Re: Programming Speed
« Reply #34 on: June 02, 2010, 07:29:01 pm »
No, it's only for a list.  I was thinking the sum(seq([exp],[var],[start],[finish] was to be used on a list (with a list as [exp] ).  Sorry about this misunderstanding. :)

Oh, got it.