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seq(X^2,X,1,3
{1,4,9}
The TI manual is very unoptimized, but how would you use sum( the way you used it? Doesn't the first argument have to be a list?
The seq() command returns a list.For example:Code: [Select]seq(X^2,X,1,3would returnCode: [Select]{1,4,9}
]WHAT?!This was in TI's manual? I hope they know that sum([exp],[start],[finish] is smaller and faster. What was TI thinking! Which manual was it, 2.43 or 2.53?
No, it's only for a list. I was thinking the sum(seq([exp],[var],[start],[finish] was to be used on a list (with a list as [exp] ). Sorry about this misunderstanding.