Okay I cannot read that without newlines I get your point, but I can understand why they do not approve "jailbreaking". TI is professional and not some open-source internet user.

Binairy

I still wonder why my code doesn't work. Do I have to count cycles??

I just mastered the famous Reset Glitch and I found out something really cool: The gamedesigners hid some anti-cheat mechanisms in Super Metroid. It's up to us gamers to find them all! I will be doing a series of video's on the anti-cheat systems and some more cool tricks you can do will all items! (pwning crocomire with the grappling beam for instance)

First video:

Hahaha, very nice. Brings back memories of seeing ads for these big bulky light/magnifiers in old gaming magazines.

Maybe I can make some sort of worm light for my calc!

Sorry if this is difficult to follow, I didn't really know how to structure the diagram (if you want to call it a diagram). If you have any questions, just ask. Otherwise, I hope this helps!

Code: [Select]

SENDER RECEIVER
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
Pull ring low

Repeat up to [ARG 2]*8μs If ring is not low, abort
 | If tip is low, break from loop Pull tip low
If tip is not low, abort

Release tip
Received byte = 0

LOOP 8 TIMES LOOP 8 TIMES
 | Release ring, pull tip low |
 | Wait ~21μs | Wait until tip == ring
 | Rotate byte to send left |
   | If 0 rotated out, pull ring low |
   | If 1 rotated out, release tip |
 | Wait ~12μs | If tip is low, rotate 0 left into byte
 | | If tip is high, rotate 1 left into byte

Release tip and ring


It's not quite clear to me when I have to add delays. This is what I understood:
Function get:
If ring is low
 Pull down tip
 Delay
 Release tip
 Set byte to 0 by default
 Loop 8 times
  Wait until tip and ring are equal
   If tip is low
    bit received is 0
  otherwise
    bit received is 1
  Delay 12μs
 End of loop
otherwise
Return -1
End
Return received byte
Added some delays. Otherwise the receiver would just receive a lot of the same (1 or 0)


Function send:
Pull ring low
Loop until time runs out
 If tip is low, break from loop
End loop
If time ran out
 Return -1;
Loop 8 times
 Release ring
 pull down tip
 Delay 21μs
 If the bit is 1
  pull ring low
 otherwise
  release tip
 Wait 12μs
End of loop
Release tip and ring

void setup(){
 pinMode(2,INPUT);
 pinMode(3,OUTPUT);
 digitalWrite(2,HIGH);//ring release
 digitalWrite(3,HIGH);//tip release
 Serial.begin(9600);
}
int Get(){
 if (digitalRead(2)==LOW) {
  digitalWrite(3,LOW);//pull tip down
  delayMicroseconds(12);
  digitalWrite(3,HIGH);//release tip
  int recvbyte=0;
  for(int i=7; i>=0; i--){
   while (digitalRead(2)!=digital
 Read(3)){}//wait until tip==ring
   if (digitalRead(2)==HIGH){
    bitSet(recvbyte,i);
   }
   while (digitalRead(2)==digitalRead(3)){}
  }
  return recvbyte;
 }
 else {
   
   return 0;
 }
 
}
void loop(){
  Serial.println(Get());
  delay(1000);
}I ported it to arduino. Lemme tell ya: It doesn't work at all :| Do I have to count cycles???

Not sure if it's him who is at fault, considering he uses an outdated Axe build or most likely did something in his code earlier, but just in case it might be a bug in AxePaint

Quote from: IRC

[15:31:30]   Keoni29   Axepaint is evil
[15:31:38]   Eiyeron   (excuse me, another reflex )
[15:31:39]   Keoni29   It screwed up my ram
[15:31:52]   Keoni29   MARCO
[15:32:22]   *   Keoni29  waitin for your reflexes to kick in
[15:32:29]   DJ_O   you might need to report the bug to the author in his topic keoni29
[15:32:44]   DJ_O   unless it's SirCmpwn, who is banned from both Omni and Cemetech
[15:33:16]   DJ_O   also aren't you sure it's not you who did something wrong?
[15:33:19]   Keoni29   Writing and reading from and to appvars is somehow corrupted
[15:33:26]   DJ_O   oh
[15:33:33]   Keoni29   My code worked just fine before
[15:33:36]   DJ_O   do you use the right Axe version?
[15:33:42]   Keoni29   1.1.1

Everything worked just fine before I used AxePaint.