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Messages - Xeda112358
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3196
« on: September 10, 2011, 06:42:14 pm »
I did! And now that I got it working properly, this is cool
Edit: Is there a source I can look at (the Axe code). I want to get a feel for how I would use Zedd
3197
« on: September 10, 2011, 06:00:41 pm »
 I would love to use this! I plan to learn Axe, now! EDIT: I cannot move objects that I have grabbed! What do I do? O.0
3198
« on: September 10, 2011, 04:13:07 pm »
It is still cool! I wish I knew how to program in C++. I would love to make a bunch of math programs in it...
EDIT:
Is math Turing Complete?
3199
« on: September 10, 2011, 04:11:39 pm »
Darn... I don't know then...
3200
« on: September 10, 2011, 04:06:36 pm »
Here is a code (that can be optimised, I bet). Also, I use programs like this all the time and my RAM clears a lot, so I make this a lot. This returns the digits backwards: While Ans
Disp 2fPart(Ans/2
iPart(Ans/2
End
It converts the number in Ans to binary. EDIT: Oh I see what you did there I was looking for your loop when I saw your code and that is a cool method! EDIT2: Here is a code like that: Disp 2fPart(Ans/2
iPart(Ans/2
If Ans
prgmC
3201
« on: September 10, 2011, 03:58:00 pm »
Ah, I should have stated n>2
3202
« on: September 10, 2011, 03:21:42 pm »
In this case, I am pretty sure the answer is yes simply because we are dealing with circles of the same radius. To test it, if the lobster particle could move in three dimensions, we should have a 1/8 chance of it ending up within a unit away. If it could only move in 2 dimensions but took an extra move, we would have a 1/9 chance. If number of steps is n, then in 2 dimensions we have (n-1) -2 and three dimensions has 2 -n. Now I want to look at 4 dimensions and higher. EDIT:... because it would necessitate another class of equation. We have the polynomial solution for 2 dimensions ((n-1) -2), n-powered polynomial solution for three dimensions. I have studied functions and have defined various types in recursive form.
f(x)=a f(0)=a ; f(x)=f(x-1)
f(x)=ax f(0)=0 ; f(x)=f(x-1)+a
f(x)=axb f(0)=0 ; f(x)=f(x-1)+a(xb-(x-1)b) ;*Needs a better form
f(x)=abx f(0)=a ; f(x)=f(x-1)b
f(x)=a(x!) f(0)=a ; f(x)=f(x-1)x
I call this "Dimensional Mathematics" in my notes, by the way, because it allows definitions of many types of equations including equations working with time itself. The latter bit is typically called an algorithm 
3203
« on: September 09, 2011, 11:09:51 pm »
Ah clever work, although I believe that you are lucky that it worked because while it does make a circle, it is not a circle where every point is of an equal probability 
Actually, I was worried about that, too, but while every part isn't equal, there is a balance to it.
3204
« on: September 09, 2011, 06:32:42 pm »
So Builderboy presented a puzzle along these lines on IRC, earlier: You have a flat surface (for all intents and purposes, 2D) A lobster is at position x (Builder said frog, Qwerty said turtle) The lobster moves 1 unit away in a random direction (any angle). It tires out after 3 moves The question is, what is the chance that Lobztor will be within 1 unit of its starting position? Here is my approach: -First draw a circle with center at point x of radius 1. This is the target region as well as all the first move positions -Choose a point on the circle as the center for a second circle of radius 1. Note that 1/3 of the circle is in the 1 unit range. -From here, draw infinitely many circles on this circle  You will notice that this creates a circle of its own with radius of 2 units! Using the powers of geometry, we find the ratio of the area of these two circles and get....1/4. Yay! It is pretty close to magic in my opinion! EDIT: Just so y'all know, that is 530 circles drawn by Grammer in that screenie at 6MHz.
3205
« on: September 06, 2011, 04:50:51 pm »
This is just my own playing around with math and I don't doubt that there is a much easier way to do this. The method I used is derived from a matrix, actually, too. However, taking the time to squish that matrix down from two dimensions to one was the long, drawn out part. I came up with this as kind of an offshoot of some bigger math problems that I was working on, but I thought it was a neat idea. So yeah, pretty much, this method takes a finite set of data and finds an equation that can model that data.
3206
« on: September 06, 2011, 04:39:43 pm »
Howdy mdjenkins86 I was going to ask for a summary of what TSOD was (as in was it a game, math program, quadratic solver, etc.), but the screenies DJ provided kind of answered that. DJ_O is just cool like that, I guess  So, yeah, welcome back!
3207
« on: September 05, 2011, 11:06:46 pm »
There are a few things that bug me about this, but before I get to those I would like to thank the person that advised me to stop. I know that I would have made matters worse if I kept that little war going, so thanks. Anyway, what bugs me is that we have shown that we can be responsible. I mean, for crying out loud, we had a religion thread that didn't end in a fight and it had several points of view present. That is not a feat that is easy to achieve, especially with many members from around the world. I had thought that we as a community had reached a new level of tolerance and I was very happy about that. I still think we have and I am personally proud to say that I got to witness that. However, tonight was an example where at least one member showed intolerance and another (myself) was almost ready to be just as bad by not respecting their opinion.
Again, I am glad that I was stopped from getting angry again because "gay bashing" is something that I particularly don't like. In retrospect, I can understand the offender's argument, but that still doesn't mean that I like it. The responsible thing, though, would have been to take the argument to a private channel. The reason why I take such offense is that not only do I have many gay, lesbian, and bisexual friends, but I am bisexual, too. I am attracted to men and I am attracted to women. If I were to marry a man or a woman, I would still want that marriage to be just as sacred and held with the same honor and, incidentally, I am getting married. The plans have been in the works for a while now, but next month will be one of the biggest days of my life and I will be marrying a woman that I would go to the ends of the earth for and that I want to be with for the rest of my life. I am just shy of 20 years old and it has been hypothesized that the first human to live to 150 years old has already been born. I am fully aware that I may get the chance to live for the next 130 years with her and I am ready for a commitment like that. So when somebody is willing to commit their whole life to start a new one with the person they love, I believe that their marriage deserves to be called a marriage, even if it is a same-sex marriage, regardless of what a dictionary says.
If this post needs to be removed for offensive material or whatnot, I will understand. Thanks and I am sorry if I offend anybody.
3208
« on: September 05, 2011, 09:26:27 pm »
So here is an update. I made a program in Python that will do the same thing as Interpl8 for the calc (pretty much). Just input the list (don't add an ending bracket or starting one) and then when it asks for the file to output to, just do something like equation.txt
3209
« on: September 03, 2011, 06:18:11 pm »
I was on the french site tout82 trying to help out with some hex codes for the 82/83 when I thought of an optimisation that applied to about ten of the codes. Here is an example:
Auto Fractions:
21FA893E0C77C9
optimises to:
3E0CFD770AC9Alpha Press Lock
21028A3ED0B677C9
optimises to:
3ED1FD7712C9
So here is v1.31
3210
« on: September 03, 2011, 10:58:57 am »
That has been helpful! I keep forgetting about TI-Freakware and that has often been the place to go for info like this! I will probably need to locate an include file so that I can look at addresses and whatnot, though. By the way, I am trying to convert Grammer, if that helps. EDIT:Here is a list of the bcalls used in Grammer:
bcall(_RclAns) ;Used at the begining.
bcall(_ChkFindSym) ;Used twice
bcall(4594h) ;used to convert a token to ASCII
As a note, bcall is the only rst used, too. So this means it shouldn't be too hard to convert, right? No bcalls are used to read FP numbers, display text, play with the LCD or anything else. I can easily make a routine to replace _ChkFindSym and _RclAns, but the last one is the one that I might have difficulty with as I don't know anything about it 
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