Thanks. Changed and added.

So the code in question is this:

ZStandard
104→Xmax
72→Ymax
ZInteger
ClrDraw
For(A,0,31
Horizontal A
End
"L1(A→u
{100621062,301030,10059.1,20359.1,30759.1,110027.1,120327.1,130727.1,201059.1,201027.1,56.2,156.2,107252.3→L1
For(A,1,dim(L1
iPart(E2fPart(u/E2→Z
iPart(E2fPart(u/E4→X
fPart(u→C
If .1=Ans
Then
iPart(10fPart(u/E5→B
iPart(u/E5
If not(Ans
Pt-On(X,Z,B
If 1=Ans
Pt-Off(X,Z,B
If 2=Ans
Pt-Change(X,Z
End
If .2=C
Then
If X
Horizontal Z
If not(X
Vertical Z
End
If .3=C
Circle(X,Z,iPart(E2fPart(u/E6)),{i
If not(C
Line(iPart(E2fPart(u/E8)),iPart(E2fPart(u/E6)),X,Z,iPart(u/E8
End
First I'll go over the compression.

Each element is checked for it's decimal point via fPart() because the type of command that is graphed is dependant on it.

0=fPart(\Number\): The data is for a Line() command.
.1=fPart(\Number\): The data is for a Pt-On()/Pt-Off()/Pt-Change() command.
.2=fPart(\Number\): The data is for a Horizontal/Vertical command.
.3=fPart(\Number\): The data is for a Circle() command.

123456789
|||||||||These two numbers are the second y-coordinates for the command.
|||||||These two numbers are the second x-coordinates for the command.
|||||These two numbers are the first y-coordinates for the command.
|||These two number are the first x-coordinates for the command.
|This number dictates if the command is turning on the line or turning it off (one if it is turning it on, zero if it is turning it off).

123456.1
|||||| |Tells the program that it is a Pt-On()/Pt-Off()/Pt-Change() command.
||||||These two numbers are the y-coordinate for the command.
||||These two numbers are the x-coordinate for the command.
||This number dictates if it is a dot, cross, or sqare point that is drawn (one for a dot,
||two for a square, three for a cross; doesn't matter what it is for Pt-Change() since
||it doesn't have a third argument).
|This number dictates if it is a Pt-On()/Pt-Off()/Pt-Change() (zero if it is Pt-On(), one if it is Pt-Off(), two if it is Pt-Change()).
123.2
||| |This number tells the program that it is a Horizontal/Vertical command.
|||These two numbers are the coordinate number.
|This number dictates whether it is a Horizontal or Vertical command (one for Horizontal, zero for Vertical).
123456.3
|||||| |This number tells the program that it is a Circle() command.
||||||These two numbers are the y-coordinate.
||||These two numbers are the x-coordinate.
||These two numbers are the radius.
Ok, not to start breaking down the code.

ZStandard
104→Xmax
72→Ymax
ZInteger
This just sets the window to Xmin=0,Xmax=94,Ymin=0, and Ymax=62.

ClrDraw
For(A,0,31
Horizontal A
End
Clears the graphscreen then fills the bottom half of the screen.

"L1(A→u
{100621062,301030,10059.1,20359.1,30759.1,110027.1,120327.1,130727.1,201059.1,201027.1,56.2,156.2,107252.3→L1
This stores the string "L1(A" to the equation variable u. Basically what it does is that each time that variable is called it will execute that "equation" each time. (Though now that I think about it that can probably be replaced with something else.)
The second line is just storing a test list to demonstrate what the program does.

Now we get into the belly of the code.

For(A,1,dim(L1
iPart(E2fPart(u/E2→Z
iPart(E2fPart(u/E4→X
fPart(u→C
This starts the loop that loops through the list. Then it stores the thousands and hundrends number to the X variable and the tens and ones numbers to the Z variable, because the Y variable can get erased. Then it stores the decimal point of the current list element to the C variable.

If .1=Ans
Then
iPart(10fPart(u/E5→B
iPart(u/E5
If not(Ans
Pt-On(X,Z,B
If 1=Ans
Pt-Off(X,Z,B
If 2=Ans
Pt-Change(X,Z
End
This is the code to display Pt-On()/Pt-Off()/Pt-Change() commands. First it stores what kind of point it is to the B variable then finds out which command it is. It then displays the correct command and type.

If .2=C
Then
If X
Horizontal Z
If not(X
Vertical Z
End
This is the code for displaying a Horizontal/Vertical command. Since only one coordinates is used we are able to use the X variable to determine which command it is and execute accordingly.

If .3=C
Circle(X,Z,iPart(E2fPart(u/E6)),{i
This code simply displays a circle. It uses the X and Z variables for the coordinates and then directly finds the the radius.

If not(C
Line(iPart(E2fPart(u/E8)),iPart(E2fPart(u/E6)),X,Z,iPart(u/E8
End
This code displays a line, or turns one off. It directly finds the first couple of coordinates and then uses the X and Y variables for the second set of coordinates. Then it just finds whether that first number was a one or zero and uses it to turn the line on or off.
The End is then the end of the For() loop.

That explain things better?

I'll also go over it all and try to optimize it some later.

Dang it, I had just optimized it but you guys beat me...

Ok, I'll explain it as best as I can. However I am really tired tonight so I will do it tomorrow after I've gotten some sleep.

Because TI sucks...um...wait...no...I mean...nevermind, that's what I mean Seriously though, I'm not sure. I'm sure someone does though. Would be nice if it was uniform or just a lot faster.

And do you mean my code here for my display routine? If so, do you first understand the compression method? Because that would be a huge part of explaining the code.

Dang it DJ, you jinxed me I moved it to the wrong place, but finally got it fixed...just need a Admin to delete the wrong one now...>.>

That's the only way you're going to bypass the 999 undo limit, unless you store to a string but then it will get really slow the bigger the string gets.