The object of the Rules Game is simple: win the Rules Game

How? Make rules.

Set-in-stone rules:

You may not make a rule that automatically makes someone win/lose the Rules Game (... wins the game, ... loses the game, "if you do this, you win," etc.)
You may not double-post. period. (even in accordance the the forum rules)
Once someone wins, they will be posted in a winners list in this post, and a new game will start.
You may not comment on other people's rules without posting a rule in the same post (just say "comment:" before you make a comment)
You may not negate other people's rules
Rules remain for the duration of a game. If you don't follow them, you are out.
Edits count as comments
Edits to a violating rule are disallowed unless made before the next rule is made.
You are not allowed to join once the first person is out.
When there are two people left, if no new rule is made within a day of the previous, the person who made the last rule wins!



Winners (so far):

epic7 with: http://ourl.ca/18745/376490


I'll start:

I like poetry
And this is a cool haiku
All rules must be too

Line clipping? I thought that that is a problem being worked on by Runer112 for future versions?

Well, yes, but here's a temporary fix, using trig!

To all those who may spot any error in my trig: please tell me. I'll try to fix it.



Inspiration:

I saw god's (leafy's) Super Hexagon port, and I saw a problem that he listed: The line clipping. I thought to myself: how do I solve this? The answer is by using trig!

Just to show you I'm not crazy: here are some screenies for a very incomplete Super Hexagon engine (I will not continue after this point because I just made it to solve a problem):



Axe trig background:

Trig in Axe is not standard to the trig you learned in school. There are no degrees or radians. There are only sine and cosine functions (of which all normal functions can be derived from). The period of these functions is 256, and the amplitude 128 (signed).
To get a sine of an angle (0-255, not 0-359), it is simply sin(angle)//127 (make sure it is // and not /, due to the output being signed). The same works with cosine.

Since my super hexagon engine is done in polar coordinates, it is easier with this case, but there is only one more step with using

Now: here's some code before I explain how to do stuff (copied from graph-link):

.HEXAGON

ExprOn

For(A,0,7)
0ü{A+L}
End

64ü{1+L}

128ü{3+L}

192ü{5+L}

0ü{7+L}

0üXüAüBüCüD
1üF
2üE
65435üW
43üO
0üR

0üGüHüIüJüKüLüMüN

Repeat (getKey(15))
D+EüD
8*(getKey(3)-getKey(2))üC
X+CüX
If (Xùú8)
248üX
ElseIf (Xù255)
0üX
End
If (Dùú2)
254üD
F++
sub(A)
ElseIf (Dù255)
0üD
F++
sub(A)
End
10*cos(X+D)üA
10*sin(X+D)üB
ClrDraw
Pxl-On(47+(A//128),31+(B//128))
Line((7*cos(0*O+D))//128+47,(7*sin(0*O+D))//128+31,(7*cos(1*O+D))//128+47,(7*sin(1*O+D))//128+31)
Line((7*cos(1*O+D))//128+47,(7*sin(1*O+D))//128+31,(7*cos(2*O+D))//128+47,(7*sin(2*O+D))//128+31)
Line((7*cos(2*O+D))//128+47,(7*sin(2*O+D))//128+31,(7*cos(3*O+D))//128+47,(7*sin(3*O+D))//128+31)
Line((7*cos(3*O+D))//128+47,(7*sin(3*O+D))//128+31,(7*cos(4*O+D))//128+47,(7*sin(4*O+D))//128+31)
Line((7*cos(4*O+D))//128+47,(7*sin(4*O+D))//128+31,(7*cos(5*O+D))//128+47,(7*sin(5*O+D))//128+31)
Line((7*cos(5*O+D))//128+47,(7*sin(5*O+D))//128+31,(7*cos(0*O+D))//128+47,(7*sin(0*O+D))//128+31)
sub(B)
DispGraph
End
Return

Lbl A
!If (F^5)
úEüE
End
Return

Lbl B
0üGüHüIüJüKüLüMüNüR
For(K,0,3)
{(2*K)+L}üH
{(2*K)+1+L}-6ü{(2*K)+1+L}
{(2*K)+1+L}/2üG
If (G÷7)
0ü{(2*K)+1+L}
{(2*K)+1+L}/2üG
End
For(L,0,5)
(G*cos(L*O+D))//128+47üI
(G*sin(L*O+D))//128+31üJ
(G*cos((L+1)*O+D))//128+47üM
(G*sin((L+1)*O+D))//128+31üN
If ((J<<0) and (N<<0))
ElseIf (J<<0)
J*sin(O-(448-(L*O+D)))//127//sin(64-(O-(448-(L*O+D))))//127+IüI
0üJ
ElseIf (N<<0)
N*sin(O-(448-((L+1)*O+D)))//127//sin(64-(O-(448-((L+1)*O+D))))//127+MüM
0üN
End
If ((J>>63) and (N>>63))
ElseIf (J>>63)
J*sin(O-(448-(L*O+D)))//127//sin(64-(O-(448-(L*O+D))))//127+IüI
63üJ
ElseIf (N>>63)
N*sin(O-(448-((L+1)*O+D)))//127//sin(64-(O-(448-((L+1)*O+D))))//127+MüM
63üN
End
!If (H=L)
Line(I,J,M,N)
End
End
End
Return

We are only concerned with this segment of code:

Lbl B
0üGüHüIüJüKüLüMüNüR
For(K,0,3)
{(2*K)+L}üH
{(2*K)+1+L}-6ü{(2*K)+1+L}
{(2*K)+1+L}/2üG
If (G÷7)
0ü{(2*K)+1+L}
{(2*K)+1+L}/2üG
End
For(L,0,5)
(G*cos(L*O+D))//128+47üI
(G*sin(L*O+D))//128+31üJ
(G*cos((L+1)*O+D))//128+47üM
(G*sin((L+1)*O+D))//128+31üN
If ((J<<0) and (N<<0))
ElseIf (J<<0)
J*sin(O-(448-(L*O+D)))//127//sin(64-(O-(448-(L*O+D))))//127+IüI
0üJ
ElseIf (N<<0)
N*sin(O-(448-((L+1)*O+D)))//127//sin(64-(O-(448-((L+1)*O+D))))//127+MüM
0üN
End
If ((J>>63) and (N>>63))
ElseIf (J>>63)
J*sin(O-(448-(L*O+D)))//127//sin(64-(O-(448-(L*O+D))))//127+IüI
63üJ
ElseIf (N>>63)
N*sin(O-(448-((L+1)*O+D)))//127//sin(64-(O-(448-((L+1)*O+D))))//127+MüM
63üN
End
!If (H=L)
Line(I,J,M,N)
End
End
End
Return

Simply put: This is the display routine for incoming sprites. If it sees a line that is clipped, it fixes it.

This is the first little bit of code:

(G*cos(L*O+D))//128+47üI
(G*sin(L*O+D))//128+31üJ
(G*cos((L+1)*O+D))//128+47üM
(G*sin((L+1)*O+D))//128+31üN

It does the polar to rectangular conversion.

G is the radius, L*O is the angle of one point relative to D (which rotates everything, so it is added here), and (L+1)*O is the other

The 47 and 31 are the coordinates for the center of the screen (the origin)

If ((J<<0) and (N<<0))
ElseIf (J<<0)
J*sin(O-(448-(L*O+D)))//127//sin(64-(O-(448-(L*O+D))))//127+IüI
0üJ
ElseIf (N<<0)
N*sin(O-(448-((L+1)*O+D)))//127//sin(64-(O-(448-((L+1)*O+D))))//127+MüM
0üN
End
If ((J>>63) and (N>>63))
ElseIf (J>>63)
J*sin(O-(448-(L*O+D)))//127//sin(64-(O-(448-(L*O+D))))//127+IüI
63üJ
ElseIf (N>>63)
N*sin(O-(448-((L+1)*O+D)))//127//sin(64-(O-(448-((L+1)*O+D))))//127+MüM
63üN
End

This is the meat of the routine. It checks if an endpoint is out of bounds (and it both are, it does nothing) (Note: This routine was written for the top and bottom of the screen to be checked, but not the sides. It follows pretty much the same process, only the coordinates are flipped and 448 is 364)

The key is the law of sines: There is a triangle formed by the top border of the screen, the vertical line of the x coordinate of the point off-screen, and the line that is being clipped. By using this (the formula above) we can calculate the x coordinate of the point on the line that is at y=0

That is all. Remember to find your angles first if you are using rectangular coordinates. If you don't feel that I explained it well enough, please let me know and tell me what I need to explain.

Best video game pickup of mine: Awesomenauts. Give it a try!

It's a side-scroller shooter MOBA. In other words, epic.

Wait: that's not what the topic is about... oops.

Looks not bad at all!
How are the controls? Are you constantly flying up from itself, since it looks a bit like that.

If up is not pressed, then down. Just arrow key controls. Thanks for asking!

I'm in I'll make some sort of a demo program, but I don't know what exactly yet.

EDIT : now that I think of it, I'll surely use an axiom I made some months ago, is it ok ?

An axiom that you made before this contest is allowed

Is inline ASM allowed?

Only if you can show me that it came from before this contest (use your best judgement here)

Hmm, I think I'm entering. I just have to think of a cool idea

Should I add you to the competitors list?

i may go and learn axe for this

Do it! It is worth it! This contest is just for experience and for fun (As I said, just for the heck of it!).

So this is like an open-ended cage match? Sounds pretty cool

Yes, yes it is.

Quote from: pimathbrainiac on April 14, 2013, 03:04:15 pm

Quote from: Juju on April 14, 2013, 02:56:30 pm

Quote from: pimathbrainiac on April 14, 2013, 01:38:15 pm

THIS IS AWESOME!

Now port Windows

* pimathbrainiac runs to Antarctica

Windows 3.1 running in DosBox. That might work.

WinCE, perhaps?

anyone up to the challenge?

Why not PalmOS?

Because I thought of WinCE first

PalmOS is a good choice too, I suppose. So long as the OS can be compiled for ARM, it's good.




Edit: WinCE and PalmOS have both been ported to ARM, so it looks like they might be possible

derp. my fault. I didn't realize that m68k was for the console itself

Out of curiosity, will this be a true emulator, or a simulator?

(for clarity: an emu emulates hardware, while a simulator simulates software)