The grass near the Cerulean cave is my fav; I once got a pokemon to jump 99 levels in one battle there

Buckeyedude, will you have that glitch implemented in this?

I hated how gust was normal type; it made viridian forest so much harder if you didn't pick charmander (and even then you have to level it to 9 first)

51- Ztris
52- Tetris Marathon
53- Cabamap
54- Elements 3.2
55- Graph3d

WIN.

Colin/Sasha isn't broken at alllllll nopeee

Sir, did you say somewhere that you weren't planning on supporting sea units? Because that would be actually very nice (gets rid of those extremely broken battleships...)

I hit "compile" on the main Axe menu and the calculator crashed....

I am not sure as to why..maybe I have too much stuff on my calc (omni, os 2.53, zStart, and mirage hooks)

Most important Pokemon glitch: the trainer-fly glitch, also known as the Mew glitch. This is the reason why I have a non-gamesharked pokemon named .4  (cooltrainer type) with the moves "         ", "TM28", "TM40", and "Gary"

I have to say this looks really nice. One of the things that made the TiBoySE version unplayable was the narrow view..though I guess that can;t be helped. However, the few major things this will have over TBSE is that all the menus and dialogue will fit on the screen at once. I am excited.

How much space does this take oncalc?

......Shat.
I kind of made an assumption that's not quite valid
Here it is though, if you want to see it



Ok, so Euler's Formula states

e^(xi)=cos x + i sinx  (or cis x)

Step 1: prove for x=0

e^0i= cos0 + i sin0
1=1+0i
1=1

Step 2 Assume true for x=k

e^(ki) = cis k

Step 3 Prove for x=k+1

e^(k+1)i=cis(k+1)       
e^(ki+i)=                         //distribute i
(e^ki)(e^i)=                     // exponent property
(cis k)(cis 1)=                    // here's where i mess up. In my original proof, I did induction the standard way, except it's really hard to prove e^i=cis 1,       so I just kind of assumed that it was true and used it here to sub it in as e^i=cis 1
(cos k +i sin k)(cos 1 + i sin 1)=   //expand
cos k cos 1 + i sin 1 cos k + i sin k cos 1 + -1 sin k sin 1   //multiply out
cos k cos 1 -sin k sin 1 + i (sin 1 cos k + sin k cos 1) =     //re order terms
cos (k+1) +i sin (k+1)                                                   //recognize cos and sin sum formulas
cis (k+1) =cis (k+1)

Subbing in pi  gives e^ (pi i) = cos pi + i sin pi
                                       =   -1    +   0i
                                       = -1

I always do this, I get an idea, I get lazy, skip a step, and then realize that it threatens the whole integrity of the proof >.<

Axe.

mmmmmmmm yeah