Author Topic: defining a function (Read 2835 times)

runeazn · « **on:** March 03, 2012, 07:33:40 pm »

ok this is my code with temp fix :

def i_to_c(inches):"
inches=inches * 2.54
return inches

def lbs_to_kg(lbs):
lbs=lbs * 0.45359237
return lbs

height = i_to_c(height)
weight = lbs_to_kg(weight)"

my first one was :"
def i_to_c(inches):
inches=inches * 2.54

def lbs_to_kg(lbs):
lbs=lbs * 0.45359237

i_to_c(height)
lbs_to_kg(weight)"

why doesnt my first code work? it should do fine me thinks.
but it still prints the first definition of that variable
while the function should redefine the variable..

ruler501 · « **Reply #1 on:** March 03, 2012, 07:36:26 pm »

because its working with a local variable and that wouldn't be able to change a global variable. If you made the names different it may work though im not sure. I havent worked with python for a while

runeazn · « **Reply #2 on:** March 03, 2012, 07:37:48 pm »

the point of my first method was is to make it versatile,
can be used many more times in the code itself and keeps it short and simple.

C0deH4cker · « **Reply #3 on:** March 03, 2012, 08:34:02 pm »

Just change it from

i_to_c(height)

to

height = i_to_c(height)

Works the same way but actually works. You may consider working with classes.

Btw, you can rewrite the two functions like so:

Code: ("Python") [Select]

def i_to_c(inches):
    return inches * 2.54

def lbs_to_kg(lbs):
    return lbs * 0.45359237

Or, even smaller:

Code: ("Python") [Select]

i_to_c=lambda(i):i*2.54
lbs_to_kg=lambda(lbs):lbs*0.45359237

runeazn · « **Reply #4 on:** March 06, 2012, 10:13:28 am »

isnt this what i did?
with my new code?

and i dont think array will do much?

Author Topic: defining a function (Read 2835 times)

runeazn

defining a function

ruler501

Re: defining a function

runeazn

Re: defining a function

C0deH4cker

Re: defining a function

runeazn

Re: defining a function