Is there a way to do this?
I think there is a relativity test for this but it escapes me.

First try:
:If {A,B,C,D,E,F,G,H,I,J,L,M,N}<>_LLTSAV

Second try:
:If (delta)List({A,B,C,D,E,F,G,H,I,J,L,M,N})<>((delta)List(_LLTSAV)

sum() has that possibility of the sums still equaling. So, I don't want to use that...

didn't test this, but will this work?

if (sum(L1=L2))=Dim(L1
[the lists match]

Edit: but first you should make sure the dimensions are the same

@player: It works!

I need to see how that evaluates! That is funky!

EDIT: I understand now! L1 and L2 performs the relativity test and returns a list. You find the sum of that list and if it's the dimensions of the original list, then execute the code...

Awesome!

didn't test this, but will this work?

Code: [Select]

if (sum(L1=L2))=Dim(L1
[the lists match]

Edit: but first you should make sure the dimensions are the same

you mean like max({1,2}=|={2,2}) which will return 1 because the are not the same?

Does anyone know which command is faster? I'd think it's max(, but I'm not sure.

I think you want min(L1=L2.  This will return 1 if L1 and L2 are equal everywhere.

no, because {1,2}={1,1} will be {1,0} of which the max is 1 even tho it is not completely equal.  That's only for if you just want to know if any are equal.  You would have to do what builderboy said (which is also what i said )

Gah, sorry, I definitely failed.  Min is correct.  Thanks for pointing it out. :