Author Topic: Mat to hex (Read 2558 times)

noahbaby94 · « **on:** February 24, 2009, 09:44:46 am »

Can someone tell me what's wrong with my program it converts a matrix to hex.

:"?→Str1
:For(A,1,8
:For(B,1,12
:det(29,[A](A,B
:If 1=length(Ans
:"0"+Ans
:Ans+Str1→Str1
:End:End
:det(17,sub(Ans,2,length(Ans)-1→Str1

I'm executing it with this.

Code: [Select]

:identity(4,Str1,0,0,12,8,0,12,0,8,1,0,8,1,0

Strangely if I do this

Code: [Select]

:identity(4,Str1,0,1,12,8,0,12,0,8,1,0,8,1,0

I get it aligned properly but up one.

simplethinker · « **Reply #1 on:** February 24, 2009, 01:30:18 pm »

Where is the problem occurring and what exactly is it?

Using your first code chunk

Code: [Select]

:identity(4,Str1,0,0,12,8,0,12,0,8,1,0,8,1,0I don't get a problem, it will fill the map completely/correctly, but the second (the one you're not having problems with)

Code: [Select]

:identity(4,Str1,0,1,12,8,0,12,0,8,1,0,8,1,0Only tiles the bottom row incompletely.

[edit] ~~You could just use det(26 to convert the matrix to a string and then use det(17 to get the binary string. For all the matrices I tried they both returned the same string.~~ Nevermind

[another edit] I think I figured out the problem. You're going 'backwards'. You're adding your previous string to the end of the new element, so if you're matrix was [[1,2,3]], your program gives "030201?"

Author Topic: Mat to hex (Read 2558 times)

noahbaby94

Mat to hex

simplethinker

Re: Mat to hex