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Matr>list(Ans,L1,L2,L3,L4,L5"?For(I,1,5Ans+sub(" .?X+çQB^SplotcrossJ|v[s][e]plotsquareTI:?^^x[xhat]CAY?^^2ZV5è[i]",32fPart(sum(expr(sub("L1L2L3L4L5",I,1))10^5-cumSum(binomcdf(4,0))))/32)+1,1Endsub(Ans,2,5
I thought there was only 1 combination that didn't have a character equivalent?
Quote from: Builderboy on October 07, 2011, 07:08:08 pmI thought there was only 1 combination that didn't have a character equivalent? I think they all have character equivalents, but not every available character equivalent is three pixels wide. That might break display in a program that assumes that width.
Quote from: JustCause on October 07, 2011, 07:09:26 pmQuote from: Builderboy on October 07, 2011, 07:08:08 pmI thought there was only 1 combination that didn't have a character equivalent? I think they all have character equivalents, but not every available character equivalent is three pixels wide. That might break display in a program that assumes that width.You're partly right. Every combination has one but there are two others that are more than three pixels wide. I think that's what he means.
true i suppose, although I would have included them, and then allowed people to remove them if they wanted to impose restrictions, as removing or excluding tokens is much easier than adding them in