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Omnimaga
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Undocumented TI-BASIC tricks
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Topic: Undocumented TI-BASIC tricks (Read 84324 times)
0 Members and 4 Guests are viewing this topic.
dysfunction
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Undocumented TI-BASIC tricks
«
Reply #105 on:
January 13, 2006, 12:38:00 pm »
That's very useful, thanks! I remember I was looking for something that would do that a while ago, but I don't remember exactly what for... but I'll remember that.
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dragon__lance
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Undocumented TI-BASIC tricks
«
Reply #106 on:
January 13, 2006, 04:05:00 pm »
QuoteBegin-CDI+13 January 2006, 7:04-->
QUOTE
(CDI @ 13 January 2006, 7:04)
my 2 cents...
int(log(#)+1 = How many digits the number is
example
Text(0,0,sub(" 00000000",1,8-int(log(S)+1)),S
will return an 8 digit number at 0,0 on the GS no matter what (if S's digits are less than
nice trick, i'll probably use it sometime >D
i may sound so noobish for asking this, but wat exactly is a memory leak? just when u use lables/ gotos and amount of free mem goes down?
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kalan_vod
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Super Veteran (Next: 3000)
Posts: 2715
Rating: +10/-0
Undocumented TI-BASIC tricks
«
Reply #107 on:
January 13, 2006, 04:59:00 pm »
QuoteBegin-dragon__lance+13 January 2006, 22:05-->
QUOTE
(dragon__lance @ 13 January 2006, 22:05)
QuoteBegin-CDI+13 January 2006, 7:04-->
QUOTE
(CDI @ 13 January 2006, 7:04)
my 2 cents...
int(log(#)+1 = How many digits the number is
example
Text(0,0,sub(" 00000000",1,8-int(log(S)+1)),S
will return an 8 digit number at 0,0 on the GS no matter what (if S's digits are less than
nice trick, i'll probably use it sometime >D
i may sound so noobish for asking this, but wat exactly is a memory leak? just when u use lables/ gotos and amount of free mem goes down?
I seen this on maxcoderz before and is nice, a memory leak I believe is when you use a loop of some kind like while or repeat, then within the loop use an exit which isn't from the main loop.
c1
-->
CODE
ec1
Lbl 1
While K!=105
getkey->K
if Ans=21:Goto 1
endc2
ec2
This would give a bad memory leak (take up ram space I believe) if 2nd is pressed within the loop.
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tifreak
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Posts: 2708
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My Kung Fu IS strong...
Undocumented TI-BASIC tricks
«
Reply #108 on:
January 13, 2006, 05:32:00 pm »
A memory leak is when the calc encounters a command that requires an End statement, but never reaches it. The reason is it keeps track of how many Ends there should be, and that eats up memory...
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Spellshaper
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This is me. Or maybe not.
Undocumented TI-BASIC tricks
«
Reply #109 on:
January 14, 2006, 01:19:00 am »
got a question:
Is there a difference between int( and iPart( ?
cause it seems to me that they give the same reults...
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CDI
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Undocumented TI-BASIC tricks
«
Reply #110 on:
January 14, 2006, 02:16:00 am »
hmm... isn't int( for positive numbers? and iPart( for anything?
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BCTurk
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Undocumented TI-BASIC tricks
«
Reply #111 on:
January 14, 2006, 03:16:00 am »
CDI is correct.
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MathStuf
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Undocumented TI-BASIC tricks
«
Reply #112 on:
January 14, 2006, 06:56:00 am »
With the bases, here's one for the maximum number of digits in any base from any base (b is old base, n is old number, c is new base):
c1-->
CODE
ec1
iPart(dim(n)*ln(b)/ln(c)+1)
c2
ec2
QuoteBegin-Spellshaper+14 January 2006, 7:19
-->
QUOTE
(Spellshaper @ 14 January 2006, 7:19)
got a question:
Is there a difference between int( and iPart( ?
cause it seems to me that they give the same reults...
iPart( goes towards 0, int( goes to the next lowest integer.
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CDI
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Undocumented TI-BASIC tricks
«
Reply #113 on:
January 14, 2006, 09:41:00 am »
QuoteBegin-MathStuf+14 January 2006, 13:56-->
QUOTE
(MathStuf @ 14 January 2006, 13:56)
With the bases, here's one for the maximum number of digits in any base from any base (b is old base, n is old number, c is new base):
c1-->
CODE
ec1
iPart(dim(n)*ln(b)/ln(c)+1)
c2
ec2
so if I do iPart(dim(42)*ln(13)/ln(10)+1) what will that do again?
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MathStuf
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Undocumented TI-BASIC tricks
«
Reply #114 on:
January 14, 2006, 11:32:00 am »
QuoteBegin-CDI+14 January 2006, 15:41-->
QUOTE
(CDI @ 14 January 2006, 15:41)
QuoteBegin-MathStuf+14 January 2006, 13:56-->
QUOTE
(MathStuf @ 14 January 2006, 13:56)
With the bases, here's one for the maximum number of digits in any base from any base (b is old base, n is old number, c is new base):
c1-->
CODE
ec1
iPart(dim(n)*ln(b)/ln(c)+1)
c2
ec2
so if I do iPart(dim(42)*ln(13)/ln(10)+1) what will that do again?
That will return the maximum amount of digits in base 10 that a 42 digit number in base 13 can take up (which is 47). But n should be either a string (change to length( in that case) or a list for dim( to work properly).
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kalan_vod
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Posts: 2715
Rating: +10/-0
Undocumented TI-BASIC tricks
«
Reply #115 on:
January 31, 2006, 08:07:00 am »
Thanks for the "please install xLIB first thing" I just used it in my MS clone.
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