Author Topic: PHP question  (Read 2762 times)

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Offline flyingfisch

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PHP question
« on: June 14, 2012, 08:58:27 pm »
OK, having a problem with PHP.

Here is the code i have:

Code: [Select]
<select name="formSelect">
<option value="value1">value1</option>
<option value="value2">value2</option>
</select>

<form action= "<?PHP echo "upload.php?" . $_POST["formSelect"]) ?>" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="userfile" id="file" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>

And its not working.

What I want it to do is make the form action equal upload.php?formSelectvalue .

Can anyone help?

EDIT:

Fixed it by putting <select> inside the <form> tags
« Last Edit: June 14, 2012, 09:15:56 pm by flyingfisch »



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Offline Deep Toaster

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Re: PHP question
« Reply #1 on: June 14, 2012, 09:48:15 pm »
Your problem is the line <?PHP echo "upload.php?" . $_POST["formSelect"]) ?> in line 6. Unmatched right paren.




Offline Sorunome

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Re: PHP question
« Reply #2 on: June 15, 2012, 10:38:52 am »
That parentheses must be a semicolon.

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Offline flyingfisch

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Re: PHP question
« Reply #3 on: June 18, 2012, 12:23:57 pm »
I have another question now.

This code should tell users to go to the new domain name, only if the domain name is not the new one.

Instead it displays it all the time.

Code: [Select]
<?PHP
$domain_name = $_SERVER['HTTP_HOST'];

if ($domain_name != "newdomain.com" || $domain_name != "www.newdomain.com") {
   echo "<p>We have a new domain name! <a href="newdomain.com">Click Here!</a></p>"
}
?>



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Offline Sorunome

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Re: PHP question
« Reply #4 on: June 18, 2012, 12:42:38 pm »
if ($domain_name != "newdomain.com" || $domain_name != "www.newdomain.com")
->
if ($domain_name != "newdomain.com" && $domain_name != "www.newdomain.com")

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Offline flyingfisch

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Re: PHP question
« Reply #5 on: June 18, 2012, 12:52:50 pm »
Oh, oh, ok. I was getting mixed up. I was thinking I needed to use "or".



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